Find the smallest 4-digit number which is divisible by 18, 24 and 32.
MathematicsClass 6CBSEAnswered 22 May 2026
Answer
Given numbers are 18, 24 and 32, we have
Thus, LCM = 2 × 2 × 2 × 2 × 2 × 3 × 3 = 288
The smallest 4-digit number = 1000
Now, we write multiples of 288, till we get a 4-digit number.
288 × 1 = 288, 288 × 2 = 576,
288 × 3 = 864, 288 × 4 = 1152
Hence, 1152 is the required number.
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