Find the greatest number which divides 82 and 132 leaving 1 and 6, respectively as remainders.
MathematicsClass 6CBSEAnswered 22 May 2026
Answer
Given numbers are 82 and 132 and the remainders are 1 and 6 respectively.
We have, 82 – 1 = 81 and 132 – 6 = 126
So, we need to find the HCF of 81 and 126
Common factor is 3 (occurring twice).
∴ HCF = 3 × 3 = 9
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