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MathematicsCLASS 6CBSE
answered 22 May 2026

Find the greatest number that will divide 455, 582 and 710 leaving remainders 14, 15 and 17 respectively.

A.VERIFIED ANSWERfact-checked by tutors

Hence, the required number is 9.
Given numbers are 455, 582 and 710 and the respective remainders are 14, 15 and 17.
We have 455 – 14 = 441, 582 – 15 = 567 and 710 – 17 = 693.
Now let us find their HCF.

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Common factors are 3 and 7.
∴ HCF = 3 × 7 = 21
Hence, the required number is 21.

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