Compute the number of ions present in 5.85 g of sodium chloride.
ScienceClass 9CBSEAnswered 27 Mar 2026
Answer
Soln:
58.5 g NaCl contains 6.023 x 1023 molecules
therefore 58.5 g NaCl contains 12.046 x 1023 ions.
Hence, 5.85 g NaCl contains 5.85 x 12.046 x 1023
58.5
= 1.2046 x 1023 ions
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