A silver ornament of mass ‘m’ gram is polished with gold equivalent to 1% of the mass of silver. Compute the ratio of the number of atoms of gold and silver in the ornament.
ScienceClass 9CBSEAnswered 27 Mar 2026
Answer
Soln:
Mass of silver = m g Mass of gold = m /100g
Number of atoms of silver = Mass/ Atomic mass X NA
= m /108NA Number of atoms of gold
= m/ 100 X197
Ratio of number of atoms of gold to silver = Au : Ag
= m/ 100 X 197 X NA : m/ 108 NA
= 108 : 100×197
= 108 : 19700 =
1 : 182.41
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