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In photosynthesis, 6 molecules of carbon dioxide combine with an equal number of water molecules through a complex series of reactions to give a molecule of glucose having a molecular formula C6 H12 O6 . How many grams of water would be required to produce 18 g of glucose? Compute the volume of water so consumed assuming the density of water to be 1 g cm-3.

ScienceClass 9CBSEAnswered 27 Mar 2026
Answer

Soln:

6CO2 + 6 H2 O Chlorophyll /Sunlight → C6 H12 O6 + 6O2

1 mole of glucose needs 6 moles of water 180 g of glucose needs (6×18) g of water 1 g of glucose will need 108/ 180 g of water.

18 g of glucose would need (108 /180) × 18 g of water = 10.8 g Volume of water used = Mass

Density

= 10.8 g/ 1g cm-3

=10.8 cm3

Science · Class 9