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Chapter 02 · Mathematics

Coordinate Geometry

Master the Cartesian plane, quadrants, distance formula, and linear graphs with complete theory, solved examples, and exercises.

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Coordinate SystemQuadrantsPlotting PointsDistance FormulaLinear GraphsKey PointsExercise 1Exercise 2

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📐Two Types of Co-ordinate Systems

In two-dimensional coordinate geometry, we generally use two types of co-ordinate systems:

  • (i) Cartesian or Rectangular Co-ordinate System — A point is represented by an ordered pair (x, y), where x is the x-coordinate and y is the y-coordinate.
  • (ii) Polar Co-ordinate System — A point is represented by an ordered pair (r, θ), where r is the radius vector (distance from origin) and θ (theta) is the vectorial angle measured from the positive x-axis.

Ordered Pair

Definition: A pair of real numbers p and q listed in a specific order — with p at the first place and q at the second — is called an ordered pair, written as (p, q). This is also known as the coordinates of a point in space.

⚠️ Note: (p, q) and (q, p) represent two different points unless p = q.

Coordinate Axes

Draw two straight lines XOX′ and YOY′ intersecting at right angles at point O. These lines are called coordinate axes or axes of reference.

Y (positive) ↑ | II | I (−, +) | (+, +) | ────────────────────O──────────────────→ X (positive) | III | IV (−, −) | (+, −) | Y′ (negative) OX → Positive x-axis OX′ → Negative x-axis OY → Positive y-axis OY′ → Negative y-axis O = Origin (0, 0)
📌Key Terminology
  • The horizontal line XOX′ is the x-axis.
  • The vertical line YOY′ is the y-axis.
  • The point O where both axes meet is called the origin. Its coordinates are (0, 0).
  • The distance measured along the x-axis is called the x-coordinate or abscissa.
  • The distance measured along the y-axis is called the y-coordinate or ordinate.
  • A point P(x, y): x is written first, y is written second.

The two coordinate axes XOX′ and YOY′ divide the plane into four regions called quadrants:

Quadrant I (XOY)x > 0 , y > 0  →  (+, +)
Both coordinates positive
Quadrant II (YOX′)x < 0 , y > 0  →  (−, +)
x negative, y positive
Quadrant III (X′OY′)x < 0 , y < 0  →  (−, −)
Both coordinates negative
Quadrant IV (Y′OX)x > 0 , y < 0  →  (+, −)
x positive, y negative

Points on the Axes

On the x-axis: The y-coordinate is zero. Points are of the form (x, 0).
On the y-axis: The x-coordinate is zero. Points are of the form (0, y).
At the origin: Both coordinates are zero → (0, 0).
📝 Example 1 — Identifying Quadrants

Q. In which quadrant do the given points lie?
(i) A(3, 4)   (ii) B(−2, 3)   (iii) C(−5, −2)   (iv) D(4, −3)   (v) E(−5, −5)

SOLUTION
PointSigns (x, y)Quadrant
A(3, 4)(+, +)I
B(−2, 3)(−, +)II
C(−5, −2)(−, −)III
D(4, −3)(+, −)IV
E(−5, −5)(−, −)III
📝 Example 2 — Points on Axes

Q. Which of the following points lie on the x-axis or y-axis?
(−3, 4), (0, 8), (2, −3), (−6, 0)

SOLUTION

(0, 8) → x-coordinate = 0 → lies on the y-axis.

(−6, 0) → y-coordinate = 0 → lies on the x-axis.

(−3, 4) and (2, −3) lie in Quadrant II and Quadrant IV respectively — neither axis.

To plot a point P(a, b) in the Cartesian plane, follow this algorithm:

1
Draw two mutually perpendicular lines on graph paper — one horizontal (x-axis) and one vertical (y-axis).
2
Mark their intersection point as O (the origin).
3
Choose a suitable scale on both axes and mark equal unit distances.
4
Start from origin. Move |a| units along OX (if a > 0) or OX′ (if a < 0). Call this point M.
5
From M, move |b| units vertically upward (if b > 0) or downward (if b < 0). This final position is P(a, b).
📝 Example 3 — Plotting a Point

Q. Plot the point (3, 4) on a graph paper.

SOLUTION

Let X′OX and Y′OY be the coordinate axes. For P(3, 4):

Y 5 · 4 · P(3,4) ● 3 · 2 · 1 · 0 ·─────────────────────── X 0 1 2 3 4 Step 1: Move 3 units right along OX → reach M(3, 0) Step 2: From M, move 4 units upward → reach P(3, 4) ✓
📝 Example 4 — Plotting Multiple Points

Q. Plot the following points: A(2, 5), B(−5, −7), C(3, −2), D(0, 5), E(5, 0).

SOLUTION
Y 5 D(0,5) ● A(2,5) ● 4 3 2 1 0 ──────────────────────────── X -1 C(3,−2) ● -2 -5 B(−5,−7) ● E(5, 0) lies on the x-axis (y = 0) D(0, 5) lies on the y-axis (x = 0) B(−5,−7) is in Quadrant III C(3,−2) is in Quadrant IV A(2, 5) is in Quadrant I
📏Distance Formula

If there are two points A(x₁, y₁) and B(x₂, y₂) on the XY plane, the distance d between them is:

AB = d = √[ (x₂ − x₁)² + (y₂ − y₁)² ]

This is derived from the Pythagorean theorem: the horizontal and vertical separations form the two legs of a right triangle, and AB is the hypotenuse.

💡 Special Cases:
• Distance from origin to point P(x, y):  OP = √(x² + y²)
• If two points lie on the x-axis (y = 0): distance = |x₂ − x₁|
• If two points lie on the y-axis (x = 0): distance = |y₂ − y₁|
📝 Example 5 — Distance Calculations

Q. Find the distance between:

(i) (5, 3) and (3, 2)    (ii) (−1, 4) and (2, −3)    (iii) (a, b) and (−b, a)

SOLUTION

(i) d₁ = √[(3 − 5)² + (2 − 3)²]

= √[(−2)² + (−1)²] = √[4 + 1] = √5 units

(ii) d₂ = √[(2 − (−1))² + (−3 − 4)²]

= √[(3)² + (−7)²] = √[9 + 49] = √58 units

(iii) d₃ = √[(−b − a)² + (a − b)²]

= √[(a + b)² + (a − b)²] = √[a² + 2ab + b² + a² − 2ab + b²] = √[2a² + 2b²] = √[2(a² + b²)] units
📈Slope-Intercept Form

The general linear equation ax + by + c = 0 can be rewritten as:

y = mx + c

where:

  • m = −a/b is called the slope (or gradient) of the line.
  • c = −c₁/b is called the y-intercept (where the line cuts the y-axis).

Steps to Draw the Graph

1
Rearrange the equation to find y in terms of x: form y = mx + c.
2
Assume three integer values of x and calculate corresponding y values.
3
Prepare a table of ordered pairs (x, y).
4
Plot these points on a graph paper using a suitable scale.
5
Join the plotted points in a straight line — this is the graph of ax + by + c = 0.
📝 Example 6 — Drawing the Graph of y = mx + c

Q. Draw the graph of the line y = mx + c.

SOLUTION

Prepare a table of values. For x = 0, y = c. For y = 0, x = −c/m. For x = −c/m, we get x = −c/m.

x0−c/m−2c/m
yc0−c
Y | / | / ← slope = m | / |/______ (x-intercept at −c/m, 0) O──────────────── X | intercept on y-axis = c (point A = OA)
Key Observations:
1. The graph changes if the signs of m and c differ.
2. m (coefficient of x) is the slope of the line.
3. c is the y-intercept (where the line crosses the y-axis), i.e., OA = c.

Special Linear Graphs

y = c (constant)A horizontal lineparallel to the x-axisat height c.
Slope = 0
x = c (constant)A vertical lineparallel to the y-axisat distance c.
Slope = undefined
y = mx (c = 0)Passes through theorigin (0, 0).
y-intercept = 0
y = x (m = 1, c = 0)Equally inclined to both axes (45°).
Passes through origin
🔄Effect of Slope m on y = mx
Value of mPosition / RotationQuadrants
m > 0 (positive, increasing)Line rotates anticlockwise as m increasesI and III
m < 0 (negative, decreasing)Line rotates clockwise as |m| increasesII and IV
m = 0Horizontal line (y = 0, the x-axis)
↕️Effect of Y-Intercept c on y = mx + c
  • Changing c to c₁, c₂, c₃ … gives parallel lines (same slope, different y-intercepts).
  • Increasing c shifts the graph upward.
  • Decreasing c shifts the graph downward.
📝 Example 7 — Effect of Signs of m and c on y = mx + c
SOLUTION

The positioning of the graph depends on the sign combination of m and c:

mcGraph Description
++Rises left to right; crosses y-axis above origin
+Rises left to right; crosses y-axis below origin
+Falls left to right; crosses y-axis above origin
Falls left to right; crosses y-axis below origin
📝 Example 8 — Draw graph of y = 3x + 6

Q. Draw the graph of y = 3x + 6. Find (i) slope (ii) y-intercept (iii) area between the line and axes.

SOLUTION

Comparing with y = mx + c:   m = 3, c = 6.

x0−2−1
y603

The line cuts the y-axis at (0, 6) and the x-axis at (−2, 0).

Y 6 ● ← y-intercept (0, 6) 5 4 3 2 1 0 ──────────────────── X -3 -2 -1 ● ← x-intercept (−2, 0) Area between line and axes = ½ × base × height = ½ × 2 × 6 = 6 square units
(i) Slope = 3  |  (ii) y-intercept = 6 units (OA = 6)  |  (iii) Area = 6 square units
  • Two perpendicular lines XOX′ and YOY′ intersecting at O are thecoordinate axes.
  • Origin O has coordinates(0, 0). The abscissa of every point on the y-axis is zero; the ordinate of every point on the x-axis is zero.
  • The four quadrants have signs: I → (+,+), II → (−,+), III → (−,−), IV → (+,−).
  • Theabscissa (x)is the perpendicular distance from the y-axis. Theordinate (y)is the perpendicular distance from the x-axis.
  • Distance formula:AB = √[(x₂−x₁)² + (y₂−y₁)²]
  • Iny = mx + c: m is the slope; c is the y-intercept.
  • y = c→ parallel to x-axis;  x = c→ parallel to y-axis.
  • For y = mx with m > 0: graph is in Quadrants I & III and rotates anticlockwise as m increases.
  • For y = mx with m < 0: graph is in Quadrants II & IV and rotates clockwise as |m| increases.
  • Changing c shifts parallel lines: increasing c moves graph up; decreasing c moves graph down.
✏️

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#Question
1In which quadrant do the given points lie?
(i) (3, −5)   (ii) (−4, 6)   (iii) (−3, −1)   (iv) (2, 5)
2Which of the given points lie on the x or y axis?
(−3, 4), (0, 8), (2, −3), (−6, 0)
3Plot the points O(0,0), A(16,0), B(16,12) on graph paper. Join OB, OA and BA. Name the figure and find its area.
4Draw the graph of y = 3x + 6. Find (i) slope (ii) intercept on y-axis (iii) area between the line and axes.
Answers:
1. (i) IV quadrant (ii) II quadrant (iii) III quadrant (iv) I quadrant
2. (0, 8) → y-axis; (−6, 0) → x-axis
3. Right triangle; Area = ½ × 16 × 12 = 96 square units
4. Slope = 3; y-intercept OA = 6 units; Area = 6 square units
  • 1. Which point lies on the x-axis?
    (a) (3, 2)
    (b) (−3, 2)
    (c) (2, 0) ✓
    (d) (1, 2)
  • 2. Which point lies on the y-axis?
    (a) (1, 3)
    (b) (0, 3) ✓
    (c) (5, 2)
    (d) (2, 3)
  • 3. Which point lies above the x-axis?
    (a) (1, 2) ✓
    (b) (2, 0)
    (c) (1, −5)
    (d) (0, −3)
  • 4. Which point lies to the left of the y-axis?
    (a) (2, 0)
    (b) (−3, 4) ✓
    (c) (4, 2)
    (d) (2, 7)
  • 5. Which point lies to the right of the y-axis?
    (a) (0, 3)
    (b) (−2, 1)
    (c) (2, −5) ✓
    (d) (−3, 2)
  • 6. Which line is parallel to y = x − 2?
    (a) y = 2x + 1
    (b) 2y = 2x − 6 ✓
    (c) 2y = x + 7
    (d) y = 3x + 1

    Reason: 2y = 2x − 6 simplifies to y = x − 3, which has slope 1 — same as y = x − 2. Parallel lines have equal slopes.

  • 7. Which point lies in the IV quadrant?
    (a) (2, 3)
    (b) (1, −4) ✓
    (c) (−2, 3)
    (d) (0, 1)
  • 8. Which point lies in the III quadrant?
    (a) (0, −3)
    (b) (2, 0)
    (c) (7, −2)
    (d) (−2, −3) ✓
  • 9. Which graph is parallel to the x-axis?
    (a) y = x + 1
    (b) y = 2 ✓
    (c) x = 3
    (d) x = 2y
  • 10. Which graph is equally inclined to both axes?
    (a) y = 2
    (b) x = 2y
    (c) 2y = x
    (d) 2y = 2x ✓ (i.e., y = x)
  • 11. The abscissa of a point is the distance of the point from:
    (a) X-axis
    (b) Y-axis ✓
    (c) Origin
    (d) None of these
  • 12. The y-coordinate of a point is the distance of that point from:
    (a) X-axis ✓
    (b) Y-axis
    (c) Origin
    (d) None of these
  • 13. If both coordinates of any point are negative, then that point will lie in:
    (a) First quadrant
    (b) Second quadrant
    (c) Third quadrant ✓
    (d) Fourth quadrant
  • 14. If the abscissa of any point is zero, then that point will lie:
    (a) on X-axis
    (b) on Y-axis ✓
    (c) at origin
    (d) None of these
  • 15. One end of a diameter of a circle is (4, −1) and the centre is (1, −3). The coordinates of the other end are:
    (a) (2, 5)
    (b) (−2, −5) ✓
    (c) (3, 2)
    (d) (−3, −2)

    Using mid-point formula: Centre = midpoint → (1, −3) = ((4+x)/2, (−1+y)/2) → x = −2, y = −5.

  • 16. The points (−2,−1), (1,0), (4,3) and (1,2) are the vertices of a:
    (a) Rectangle
    (b) Parallelogram ✓
    (c) Square
    (d) Rhombus
  • 17. The distance of the point (3, 5) from the x-axis is:
    (a) √34
    (b) 3
    (c) 5 ✓
    (d) None of these

    The distance from the x-axis is simply the ordinate (y-coordinate) = 5.

Answers to Exercise 1:
1.(c) · 2.(b) · 3.(a) · 4.(b) · 5.(c) · 6.(b) · 7.(b) · 8.(d) · 9.(b) · 10.(d) · 11.(b) · 12.(a) · 13.(c) · 14.(b) · 15.(b) · 16.(b) · 17.(c)
#Question
1Plot the points in the plane if coordinates are: A(5,0), B(0,3), C(7,2), D(−4,3), E(−3,−2) and F(3,−2).
2In which quadrant do the following points lie? A(2,3), B(−2,3), C(−3,−5), D(3,−1). Explain with reasons.
3

Plot the following pairs of numbers as points in the Cartesian plane:
 

x−3−2840
y5038−2
4With rectangular axes, plot O(0,0), A(4,0) and C(0,6). Find the coordinates of the fourth point B such that OABC forms a rectangle.
5Plot P(−3,1) and Q(2,1) in the rectangular coordinate system. Find all possible coordinates of the other two vertices of a square having P and Q as two adjacent vertices.
6Find the value of x if the distance between (x, −1) and (3, 2) is 5.
7The base AB of two equilateral triangles ABC and ABC′ with side 2a lies along the x-axis such that the midpoint of AB is at the origin. Find the coordinates of C and C′.
8Name the quadrants in which the following points lie: (a) (2, 3) (b) (3, −2).
9Determine the slope and y-intercept of the graph of y = (1/2)x − 2.
10Draw the graph of the equation y = 2x + 3.
11Draw the graph of y = 4x. From the graph find the value of y when x = 2.
15Draw the graph of 3x + 6y = 12. Find the coordinates of the point where the graph cuts the y-axis.
16Draw the graph of x + 10 = 0. What type of graph is it?
17The points (2, 5) and (3, 5) are plotted in xy plane. Find the slope and y-intercept of the line joining the points. [Hint: both points have same y-coordinate]
18Draw the graphs of (i) y = x, (ii) y = x + 1, (iii) y = x + 2 on the same axes.
19Draw the graphs of (i) y = 2x, (ii) y = 2x + 1, (iii) y = 2x + 3 on the same axes.
20Draw the graphs of (i) y = 2x, (ii) y = 3x, (iii) y = 4x on the same axes.
Selected Answers to Exercise 2:
2. A → I, B → II, C → III, D → IV
4. B = (4, 6)
5. Other vertices: (−3, 6) & (2, 6) or (−3, −4) & (2, −4)
6. x = 7 or x = −1
7. C = (0, a√3), C′ = (0, −a√3)
8. (a) Quadrant I   (b) Quadrant IV
9. Slope = 1/2, y-intercept = −2
11. When x = 2, y = 8 (from y = 4x)
15. Graph cuts y-axis at (0, 2)
16. x = −10 is a vertical line parallel to the y-axis
17. Slope = 0 (horizontal line), y-intercept = 5
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