What is the TSA formula for a hollow sphere
The Total Surface Area (TSA) formula for a hollow sphere (spherical shell) with inner radius r₁ and outer radius r₂ is TSA = 4πr₂² + 4πr₁² = 4π(r₂² + r₁²), which accounts for both the outer sphere surface and the inner sphere surface. This formula recognizes that a hollow sphere has two distinct surfaces requiring measurement—the larger outer surface and the smaller inner surface—and TSA includes both since they're both part of the object's complete boundary.
This differs from a solid sphere (TSA = 4πr²) which has only one surface. For hollow spheres, you must consider both surfaces for complete surface measurement. Practical applications include: calculating material for manufacturing hollow ball bearings (both surfaces need finishing), determining coating requirements for spherical pressure vessels (inside and outside both need protection), analyzing heat transfer through spherical tanks (heat passes through both surfaces), and designing architectural domes with thickness (both surfaces are exposed). If calculating only the outer surface (4πr₂²), you might underestimate paint or coating needs since the inner surface also exists. If the shell thickness is t, then r₂ = r₁ + t, and you can express TSA alternatively as 4π(r₁² + (r₁+t)²), though the standard form TSA = 4π(r₂² + r₁²) is more straightforward when both radii are known. For extremely thin shells (t << r), the TSA approximates 8πr² where r is the average radius, representing two nearly coinciding spherical surfaces. When solving problems involving hollow spheres, clearly identify inner and outer radii, determine whether you need only one surface or both (TSA includes both), and apply the appropriate formula. Understanding the hollow sphere TSA formula demonstrates how geometric formulas adapt when shapes become more complex, adding inner surfaces that must be accounted for in comprehensive measurements.
Suggested Q&A
General · Class 12- GeneralClass 12Electric Field at Centre of Ring with Non-Uniform Charge Distribution. Four quadrants carry linear charge densities: +2λ, −2λ, +λ, −λ. Find electric field at centre.
- GeneralClass 12P°(hexane) = 408 Torr, P°(heptane) = 141 Torr. x(hexane) = 0.300. Find Y₆ and Y₇.
- GeneralClass 122N₂O₅(g) → 4NO₂(g) + O₂(g). Initial P = 50 mmHg; P at 30 min = 87.5 mmHg. Find P at 60 min.
- GeneralClass 12What is the difference between psychosis and neurosis?
- GeneralClass 12What is the difference between prism and a pyramid?
- GeneralClass 12What is the difference between phrase and clause?