Electric Field at Centre of Ring with Non-Uniform Charge Distribution. Four quadrants carry linear charge densities: +2λ, −2λ, +λ, −λ. Find electric field at centre.
GeneralClass 12CBSEAnswered 22 May 2026
Answer
For a quarter-circle arc of linear charge density λ and radius R, the field at the centre has magnitude:
E_quadrant = (√2 λ) / (4πε₀R)
Direction: along the bisector of the quadrant, pointing away from arc (for +λ) or toward arc (for −λ).
Resolving all four quadrant fields into x and y components:
Ex = [−2 − 2 + 1 + 1] × (λK/√2) = −2λK/√2
Ey = [−2 + 2 + 1 − 1] × (λK/√2) = 0
Magnitude:
|E| = 2λK/√2 = λ / (2πε₀R)
Answer: E = λ / (2πε₀R), directed along the negative x-axis
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