P°(hexane) = 408 Torr, P°(heptane) = 141 Torr. x(hexane) = 0.300. Find Y₆ and Y₇.
GeneralClass 12CBSEAnswered 22 May 2026
Answer
Step-1: Partial pressures:
P(hexane) = 0.300 × 408 = 122.4 Torr
P(heptane) = 0.700 × 141 = 98.7 Torr
Step-2: Total pressure:
P_total = 122.4 + 98.7 = 221.1 Torr
Step-3: Vapour mole fractions:
Y₆ (hexane) = 122.4 / 221.1 ≈ 0.554
Y₇ (heptane) = 98.7 / 221.1 ≈ 0.446
Answer: Y₆ ≈ 0.554, Y₇ ≈ 0.446
Suggested Q&A
General · Class 12- GeneralClass 12Electric Field at Centre of Ring with Non-Uniform Charge Distribution. Four quadrants carry linear charge densities: +2λ, −2λ, +λ, −λ. Find electric field at centre.
- GeneralClass 122N₂O₅(g) → 4NO₂(g) + O₂(g). Initial P = 50 mmHg; P at 30 min = 87.5 mmHg. Find P at 60 min.
- GeneralClass 12What is the difference between psychosis and neurosis?
- GeneralClass 12What is the difference between prism and a pyramid?
- GeneralClass 12What is the difference between phrase and clause?