What is the Mass of 10 Mole of Sodium Sulphite
To find the mass of 10 moles of sodium sulphite, we first need to determine its molecular formula and calculate its molar mass. Sodium sulphite has the chemical formula Na₂SO₃, containing 2 sodium atoms, 1 sulfur atom, and 3 oxygen atoms. The molar mass is calculated by adding the atomic masses: (2 × 23) + 32 + (3 × 16) = 46 + 32 + 48 = 126 grams per mole. Therefore, the mass of 10 moles of sodium sulphite = 10 × 126 = 1,260 grams or 1.26 kilograms.
This calculation demonstrates fundamental stoichiometry principles essential in chemistry. The relationship between moles and mass is given by: mass = number of moles × molar mass. Understanding this allows chemists to: convert between moles (counting particles at molecular level) and grams (measurable quantities), calculate reactant amounts needed for chemical reactions, determine product yields, and perform quantitative chemical analysis. The mole concept bridges the microscopic world of atoms and molecules with the macroscopic world of laboratory measurements—one mole contains Avogadro's number (6.022 × 10²³) of particles, whether atoms, molecules, or ions. When solving such problems: identify the correct chemical formula (sodium sulphite is Na₂SO₃, different from sodium sulfate Na₂SO₄ or sodium sulfide Na₂S), use accurate atomic masses (Na = 23, S = 32, O = 16), calculate molar mass correctly, and multiply by the number of moles given. Sodium sulphite is used industrially as a preservative in food and beverages, as a reducing agent in chemical processes, in photography, and in water treatment. Understanding mass-mole relationships is crucial for: chemistry laboratory work (preparing solutions of specific concentrations), industrial chemistry (scaling reactions from lab to production), pharmaceuticals (ensuring correct drug dosages), and environmental science (calculating pollutant amounts). This fundamental chemical calculation represents essential quantitative thinking that enables practical applications of chemistry across numerous fields where precise composition and amount calculations determine success in research, manufacturing, and quality control.
Suggested Q&A
General · Class 12- GeneralClass 12Electric Field at Centre of Ring with Non-Uniform Charge Distribution. Four quadrants carry linear charge densities: +2λ, −2λ, +λ, −λ. Find electric field at centre.
- GeneralClass 12P°(hexane) = 408 Torr, P°(heptane) = 141 Torr. x(hexane) = 0.300. Find Y₆ and Y₇.
- GeneralClass 122N₂O₅(g) → 4NO₂(g) + O₂(g). Initial P = 50 mmHg; P at 30 min = 87.5 mmHg. Find P at 60 min.
- GeneralClass 12What is the difference between psychosis and neurosis?
- GeneralClass 12What is the difference between prism and a pyramid?
- GeneralClass 12What is the difference between phrase and clause?