Two resistors with resistances 5 Ω and 10 Ω respectively are to be connected to a battery of emf 6V so as to obtain minimum and maximum current flowing a) How will you connect the resistances in each case? Calculate the strength of the total current in the circuit in the two cases.

Given, R1 = 5 Ω

R2 = 10 Ω V = 6V

1. When the two resistors are connected in series, minimum current flows through the When the resistors are connected in parallel, the current flow will be maximum.
2. When the resistors are in series, Total resistance = 5 + 10 = 15Ω 1/R = 1/R1 + 1/R2

1/R = 1/5 + 1/10

1/R = 3/10 R = 10/3 Ω

Therefore, the total current drawn by the circuit = V/R = 6/(10/3) = 1.8amps