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A potential difference of 4V is applied to two resistors of 6Ω and 2 Ω connected in series. Calculate: a) the combined resistance b) the current flowing the potential difference across the 6 Ω resistor

ScienceClass 10ICSEAnswered 27 Mar 2026
Answer

Given, V = 4V

R1 = 6 Ω R2 = 2 Ω

  1. Combined resistance, R = R1 + R2 = 8 ohm
  1. Current flowing, I = V/R = 4/8 = 5 amp
  1. Potential difference across 6 ohm resistor = IR1 = 3V

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