Name the two factors on which water potential depends? Also give its relationship with them.
GeneralClass 12AllAnswered 27 Mar 2026
Answer
Water potential (Ψ<sub>w</sub>) depends on two components:
|
Factor |
Symbol |
Nature |
Effect on Ψ<sub>w</sub> |
|
Solute Potential (Osmotic Potential) |
Ψ<sub>s</sub> |
Always negative or zero |
Decreases Ψ<sub>w</sub> |
|
Pressure Potential (Turgor Pressure) |
Ψ<sub>p</sub> |
Can be positive or negative |
Increases (if +ve) or decreases (if -ve) Ψ<sub>w</sub> |
Relationship:
Ψ<sub>w</sub> = Ψ<sub>s</sub> + Ψ<sub>p</sub>
Detailed Explanation:
- Solute Potential (Ψ<sub>s</sub>):
- Effect of dissolved solutes
- Always ≤ 0 (negative or zero)
- Pure water: Ψ<sub>s</sub> = 0
- More solutes → more negative Ψ<sub>s</sub>
- Pressure Potential (Ψ<sub>p</sub>):
- Physical pressure on water
- Positive in turgid cells
- Negative in xylem (tension)
- Zero at atmospheric pressure
Special Cases:
- Pure water at atmospheric pressure: Ψ<sub>w</sub> = 0 + 0 = 0 (reference point)
- Fully turgid cell: Ψ<sub>w</sub> = 0 (when Ψ<sub>p</sub> = |Ψ<sub>s</sub>|)
- Plasmolyzed cell: Ψ<sub>p</sub> = 0, so Ψ<sub>w</sub> = Ψ<sub>s</sub> (negative)
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