In 10s a charge of 25C leaves a battery and 200J of energy are delivered to an outside circuit as a result. a) What is the potential difference across the battery? What current flows from the battery?
ScienceClass 10ICSEAnswered 27 Mar 2026
Answer
Given,
Time taken, t = 10s Charge moved, Q = 25C
Energy delivered is work done = 200J
- Potential difference = (work done)/(charge moved) = (200)/(25) = 8V
- I = Q/t = 25/10 = 5A