If the charge on an electron is 1.6 × 10-19 coulombs, how many electrons should pass through a conductor in 1 second to constitute 1 ampere current?

Given,

Charge moved = 1.6 × 10-19 coulombs Current, I = 1A

Time taken, t = 1s We know that,

I = Q/t 1 = Q/1 Q = 1C

We also know that when the charge is 1.6 × 10-19 coulombs, the number of electrons present is 1 Therefore, when a charge of 1 coulomb is present, the number of electrons is given as:

(1)/( 1.6 × 10-19) = 0.625 × 10-19 = 6.25 × 1018