Find the product by suitable rearrangement:8 × 391 × 1252 × 1234 × 50
MathematicsClass 6CBSEAnswered 22 May 2026
Answer
I. 8 × 391 × 125 = 391 × (125 × 8)
= 391 × 1000
= 391,000
II. 2 × 1234 × 50 =1234 × (2 × 50)
= 1234 × 100
= 123,400
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