A car accelerates uniformly from 10 m/s to 20 m/s in 5 seconds. What is the distance covered by the car during this time?

Initial velocity (u) = 10 m/s
Final velocity (v) = 20 m/s
Time (t) = 5 s

First, calculate acceleration (a) using v = u + at:
20 = 10 + a * 5
10 = 5a
a = 2 m/s²

Now, calculate displacement (s) using s = ut + (1/2)at²:
s = (10 * 5) + (1/2) * 2 * (5)²
s = 50 + (1/2) * 2 * 25
s = 50 + 25
s = 75 meters.

Alternatively, using v² = u² + 2as:
20² = 10² + 2 * 2 * s
400 = 100 + 4s
300 = 4s
s = 300 / 4 = 75 meters.