Statistics
Mathematics · Class 10 · All
Which formula is used to calculate the median of grouped data?
All 65 questions in this quiz
Which statement best summarizes the chapter "Statistics"?
- The chapter studies only arithmetic calculations.
- The chapter introduces grouped frequency distributions, cumulative frequencies, ogives, and the calculation of the median using the standard statistical formula, enabling students to analyze and interpret real-life data effectively.
- The chapter focuses only on circles.
- The chapter has no practical applications.
Which statement about cumulative frequency is correct?
- It always decreases.
- It is obtained by successively adding frequencies.
- It is always equal to one.
- It is smaller than every frequency.
Which chapter mainly introduces the calculation of the median for grouped data?
- Probability
- Statistics
- Surface Areas and Volumes
- Trigonometry
Which quantity is NOT directly required in the median formula?
- Lower boundary
- Frequency of the median class
- Radius
- Class width
Which measure divides the observations into two equal parts?
- Mean
- Median
- Mode
- Range
If the total frequency is 80, then N/2 equals:
- 20
- 30
- 40
- 80
If the frequencies are 5, 8, 7, and 10, the total frequency is:
- 20
- 25
- 30
- 35
Which of the following is essential before applying the median formula?
- Finding the highest frequency
- Calculating cumulative frequencies
- Drawing a pie chart
- Finding the range
Which graph is commonly associated with finding the median graphically?
- Bar Graph
- Histogram
- Ogive
- Pie Chart
The class width in the median formula is represented by:
- f
- h
- N
- cf
What does "cf" represent in the median formula?
- Class Frequency
- Cumulative Frequency before the Median Class
- Central Frequency
- Continuous Frequency
The total frequency of a grouped frequency distribution is represented by:
- h
- l
- N
- cf
Which formula is used to calculate the median of grouped data?
- Mean = Sum of observations / Number of observations
- Median = l + [(N/2 − cf)/f] × h
- Mode = Highest frequency
- Range = Highest − Lowest
The median class is the class interval whose cumulative frequency is:
- Equal to the highest frequency
- First greater than or equal to N/2
- Equal to zero
- Always the last class
Which measure of central tendency is the primary focus of Class 10 Statistics?
- Mean only
- Median of grouped data
- Mode only
- Range
If mean of 8 numbers is 25, what is their sum?
- 150
- 175
- 200
- 225
Mode of 6, 6, 7, 8, 8, 8, 9 is:
- 6
- 7
- 8
- 9
Median of data 2, 6, 8, 10, 12, 14, 16 is:
- 8
- 10
- 12
- 14
If all observations are same (5, 5, 5, 5), what is mean?
- 0
- 5
- 10
- 20
Find range of: 12, 45, 20, 30, 10
- 25
- 30
- 35
- 40
Mean of 10, 20, 30, 40, x is 30. Find x.
- 40
- 50
- 60
- 70
Find median of 5, 1, 9, 3, 7
- 3
- 5
- 7
- 9
Find mode of: 1, 2, 2, 3, 4, 4, 4, 5
- 2
- 3
- 4
- 5
If mean of 5 numbers is 20, find their total sum.
- 80
- 90
- 100
- 110
Find mean of first five natural numbers.
- 2
- 3
- 4
- 5
Find median of: 10, 20, 30, 40, 50, 60
- 25
- 30
- 35
- 40
Mean of 4, 8, x, 12, 16 is 10. Find x.
- 8
- 10
- 12
- 14
Find mode of: 2, 3, 3, 5, 7, 3, 9
- 2
- 3
- 5
- 7
Find the median of: 3, 7, 9, 15, 21
- 7
- 9
- 15
- 10
Find the mean of the following data: 2, 4, 6, 8, 10
- 5
- 6
- 7
- 8
Sum of 15 numbers is 435. Mean is
- 30
- 28
- 29
- none
Mean of (a+b)/2 and (a–b)/2 is
- (a+b)/4
- (a–b)/4
- a/2
- none
Marks 140,153,148,150,154. Mean is
- 129
- 139
- 149
- 159
Mean of first six prime numbers is
- 6.8
- 3.6
- 5.6
- 5.2
Mean of first 5 multiples of 5 is
- 14
- 16
- 13
- 15
Averages: A&B=25, B&C=28, C&A=21. Average of A,B,C is
- 23.66
- 25.66
- 26.66
- 24.66
Sum of deviations from 50 is –10, from 46 is 70. Mean is
- 49.75
- 49.5
- 49
- none
Average age of 5 teachers=28. One excluded, mean reduces by 2. Age of excluded teacher is
- 26 years
- 33 years
- 36 years
- none
Girls avg=68, boys avg=62, class avg=64. Ratio of girls to boys is
- 1:2
- 1:1
- 2:3
- 3:5
Mean of 20 numbers=15. If 2 added to first 10, new mean is
- 13
- 30
- 16
- 17
Median found graphically from
- Histogram
- Frequency polygon
- Frequency polygon
- Ogive
Number of students who got below/equal to 50% marks (from ogive)
- 5
- 10
- 15
- 20
If 13 replaced by 28 in data 24,17,13,24,26,20,26,30,8,41,24. New median is
- 20
- 17
- 13
- 24
Mid value 60, class size 10. Upper and lower limits are
- 65 & 55
- 45 & 55
- 35 & 45
- 25 & 35
Ogive of 100 students marks. Median mark (approximately) is
- 40
- 50
- 55
- 60
Which is NOT a measure of central tendency
- Mean
- Median
- Mode
- Standard deviation
Mean of discrete frequency distribution is given by
- Σfx/Σf
- Σf/Σx
- Σfx
- Σx/n
Mean of 9 observations is 36. First 5 mean=32, last 5 mean=39. 5th observation is
- 31
- 43
- 28
- 37
Arithmetic mean of 1,2,3,...n is
- (n+1)/2
- n/2
- (n–1)/2
- n/2+1
Class size of class interval 20–35 is
- 5
- 10
- 20
- 15
Class mark of class interval 20–60 is
- 30
- 40
- 50
- 20
Mid-value of class interval is 45, class size=10. Upper and lower limits are
- 45 & 35
- 60 & 40
- 50 & 40
- 40 & 30
Median from class distribution 5–10(5),10–15(6),15–20(15),20–25(10)...
- 20.5
- 19.511
- 18.5
- 15.5
If mode=25 for: 15,20,25,18,14,15,25,15,18,16,20,25,20,x,18. Value of x is
- 20
- 15
- 14
- 25
Mode of: 120,110,130,110,120,140,130,120,140,120
- 140
- 120
- 130
- 110
Median from frequency distribution x={1..9}, f={8,10,11,16,20,25,15,9,6}
- 9
- 6
- 8
- 5
Median of wages: Rs 20,25,17,18,8,15,22,11,9,14
- 17
- 19
- 16
- 15
Mean of distribution=1.46. Find missing frequencies f1,f2 where total=200.
- 78 and 40
- 76 and 38
- 90 and 30
- 20 and 80
Mean of 6 numbers is 43. One excluded, mean of remaining is 41. Excluded number is
- 53
- 84
- 12
- 78
Bus: P to Q at 60kmph, Q to P at 90kmph. Average speed is
- 72 kmph
- 30 kmph
- 150 kmph
- 75 kmph
Empirical formula for mode is
- Mode=2median–3mean
- Mode=3median–2mean
- Mode=5median–4mean
- Mode=4median–5mean
Mid points of class intervals are called
- mean
- range
- median
- class-mark
Family sizes 1–3(7), 3–5(8), 5–7(2), 7–9(2), 9–11(1). Mode is
- 5.6
- 3.28
- 7.59
- 8.29
Find mean of grouped data: 0–10(5),10–20(18),20–30(15),30–40(16),40–50(6)
- 26
- 28
- 25
- 30
Mean of data is 12, find p: x={4,8,p,16,20}, f={5,3,12,5,4}
- 10
- 12
- 14
- 15