Dual Nature of Radiation and Matter
Physics · Class 12 · All
The de Broglie wavelength of a particle increases if:
All 15 questions in this quiz
Which one of the following statements best illustrates the wave-particle duality of light?
- Light exhibits only wave nature.
- Light exhibits only particle nature.
- Light exhibits wave nature in interference and particle nature in the photoelectric effect.
- Light behaves as a particle only in vacuum.
An electron and a proton have the same kinetic energy. Which one has the larger de Broglie wavelength?
- Proton
- Electron
- Both have the same wavelength
- Cannot be determined
Which statement correctly explains why photoelectric emission does not occur below the threshold frequency, regardless of the intensity of light?
- The intensity is insufficient to heat the metal.
- Individual photons do not possess the minimum required energy.
- The emitted electrons collide with each other.
- The work function decreases with increasing intensity.
The stopping potential required to stop the photoelectrons is 2.5 V. The maximum kinetic energy of the emitted photoelectrons is:
- 1.25 eV
- 2.5 eV
- 5.0 eV
- 10 eV
The threshold wavelength of a metal is 400 nm. Photoelectric emission will occur when the incident light has a wavelength of:
- 450 nm
- 500 nm
- 400 nm
- 350 nm
In a photoelectric experiment, the frequency of the incident light is doubled while its intensity remains unchanged. The maximum kinetic energy of the emitted photoelectrons will:
- Remain unchanged
- Increase
- Decrease
- Become zero
The de Broglie wavelength of a particle increases if:
- Its momentum increases
- Its velocity increases
- Its mass increases
- Its momentum decreases
The Davisson–Germer experiment provided experimental verification of:
- Maxwell's electromagnetic theory
- Newton's corpuscular theory
- de Broglie's hypothesis
- Einstein's theory of relativity
The momentum of a photon of wavelength λ is given by:
- p = hλ
- p = h/λ
- p = hc/λ
- p = λ/h
The work function of a metal is 2.2 eV. The threshold frequency is approximately: (Given: 1 eV = 1.6 × 10^(-19) J, h = 6.63 × 10^(-34) J s)
- 3.5 × 10^14 Hz
- 4.8 × 10^14 Hz
- 5.3 × 10^14 Hz
- 8.0 × 10^14 Hz
The de Broglie wavelength associated with a moving particle is given by:
- λ = mv/h
- λ = h/mv
- λ = hc/E
- λ = E/h
The stopping potential in a photoelectric experiment depends primarily on:
- Intensity of incident light
- Area of the metal surface
- Frequency of incident light
- Number of emitted electrons
According to Einstein's photoelectric equation, increasing the intensity of incident light while keeping its frequency above the threshold frequency unchanged will:
- Increase the maximum kinetic energy of photoelectrons
- Increase the number of emitted photoelectrons
- Increase the stopping potential
- Increase the work function
The work function of a metal is 2.5 eV. Which of the following incident photon energies will produce photoelectric emission?
- 1.5 eV
- 2.0 eV
- 2.5 eV
- 3.0 eV
Light of frequency 8 × 10^14 Hz falls on a metal surface whose threshold frequency is 5 × 10^14 Hz. If Planck's constant is 6.63 × 10^(-34) J s, the maximum kinetic energy of the emitted photoelectrons is:
- 9.95 × 10^(-20) J
- 1.99 × 10^(-19) J
- 3.98 × 10^(-19) J
- 5.30 × 10^(-19) J