Atoms
Physics · Class 12 · All
An electron in a hydrogen atom jumps from the fourth orbit to the second orbit. The emitted spectral line belongs to the:
All 15 questions in this quiz
Which statement correctly explains why the hydrogen atom produces a line spectrum instead of a continuous spectrum?
- Electrons may possess any amount of energy.
- Electrons occupy only discrete energy levels.
- The nucleus emits visible light continuously.
- Electrons continuously lose energy while revolving.
The shortest wavelength in the Lyman series corresponds to the transition:
- n = 2 to n = 1
- n = 3 to n = 1
- n = 4 to n = 1
- n = infinity to n = 1
Which one of the following is a limitation of Rutherford's atomic model?
- It explained the existence of the nucleus.
- It explained alpha-particle scattering.
- It could not explain the stability of atoms.
- It correctly predicted the hydrogen spectrum.
The frequency of the radiation emitted during an electronic transition is determined by:
- Speed of the electron in the orbit
- Radius of the orbit only
- Difference in energy between the two orbits
- Mass of the nucleus only
According to Bohr's theory, radiation is emitted by a hydrogen atom when an electron:
- Revolves in a stationary orbit.
- Moves from a lower energy orbit to a higher energy orbit.
- Moves from a higher energy orbit to a lower energy orbit.
- Revolves around the nucleus with constant speed.
An electron in a hydrogen atom jumps from the fourth orbit to the second orbit. The emitted spectral line belongs to the:
- Lyman series
- Balmer series
- Paschen series
- Brackett series
The Lyman series of hydrogen lies in the:
- Infrared region
- Microwave region
- Visible region
- Ultraviolet region
According to the Rydberg formula, the wavelength of the emitted radiation is given by:
- λ = R(n2² − n1²)
- 1/λ = R(1/n1² − 1/n2²)
- λ = hc/E
- λ = h/mv
The spectral lines of the Balmer series are obtained when an electron in a hydrogen atom falls to:
- n = 1
- n = 2
- n = 3
- n = 4
The excitation energy required to excite a hydrogen atom from the ground state (n = 1) to the first excited state (n = 2) is:
- 3.4 eV
- 10.2 eV
- 13.6 eV
- 1.89 eV
The ionization energy of the hydrogen atom in its ground state is:
- 3.4 eV
- 10.2 eV
- 13.6 eV
- 27.2 eV
Which observation from Rutherford's alpha-particle scattering experiment led to the conclusion that most of the atom is empty space?
- All alpha particles were reflected.
- Most alpha particles passed through the foil without any deflection.
- Alpha particles lost all their energy inside the foil.
- Electrons were emitted from the foil.
The radius of the second Bohr orbit of the hydrogen atom is: (Given: Bohr radius a0 = 0.529 × 10^(-10) m)
- 0.529 × 10^(-10) m
- 1.058 × 10^(-10) m
- 2.116 × 10^(-10) m
- 4.232 × 10^(-10) m
The energy of an electron in the third Bohr orbit of a hydrogen atom is:
- -13.6 eV
- -3.4 eV
- -1.51 eV
- -0.85 eV
According to Bohr's model of the hydrogen atom, the angular momentum of an electron in the nth orbit is:
- nh/π
- nh
- nh/2π
- h/2nπ