Application of Integrals
Mathematics · Class 12 · All
The area enclosed by a curve is always
All 15 questions in this quiz
In applications of integrals, definite integration is mainly used because it gives
- The derivative of a function
- The equation of the tangent
- The exact accumulated value over an interval
- The inverse of a function
Which of the following is the correct procedure for finding the area between two curves?
- Differentiate both curves and subtract
- Integrate the product of the curves
- Integrate (Upper Curve minus Lower Curve) over the interval
- Integrate (Lower Curve minus Upper Curve) without checking
If two curves intersect at only one point, then the area enclosed between them is
- Always positive
- Zero
- Generally cannot form a closed bounded region
- Always equal to 1
Find the area enclosed between the curves y = x squared and y = 4 from x = -2 to x = 2
- 16/3 square units
- 32/3 square units
- 8 square units
- 64/3 square units
The area enclosed between the line y = x and the x-axis from x = 0 to x = 3 is
- 3 square units
- 9/2 square units
- 6 square units
- 9 square units
The area enclosed by a curve is always
- Negative
- Positive or zero
- Equal to the definite integral without considering sign
- Always greater than 1
If a curve is symmetric about the y-axis, then the area bounded by the curve from x = -a to x = a is
- integral from -a to a of f(x) dx
- 2 x integral from 0 to a of f(x) dx
- integral from 0 to a of f(x) dx
- Zero
If two curves intersect at x = a and x = b, then the limits of integration for finding the enclosed area are
- 0 and 1
- The points of intersection
- The maximum values of y
- Any convenient values
The area enclosed between the curve y = 4 and the x-axis from x = 1 to x = 5 is
- 4 square units
- 8 square units
- 16 square units
- 20 square units
Find the area enclosed between the curves y = x and y = x squared from x = 0 to x = 1
- 1/3 square units
- 1/6 square units
- 1/2 square units
- 2/3 square units
The area between the curves y = f(x) and y = g(x), where f(x) >= g(x) on [a, b], is
- integral from a to b of [f(x) + g(x)] dx
- integral from a to b of [f(x) - g(x)] dx
- integral from a to b of f(x)g(x) dx
- integral from a to b of [g(x) - f(x)] dx
If the graph of a function lies completely below the x-axis between x = a and x = b, then the definite integral from a to b of f(x) dx is
- Positive
- Negative
- Zero
- Always equal to 1
The area enclosed between the curve y = x squared and the x-axis from x = 0 to x = 2 is
- 4/3 square units
- 8/3 square units
- 4 square units
- 8 square units
The area bounded by the curve y = f(x), the x-axis, and the lines x = a and x = b is given by
- f(b) - f(a)
- integral from a to b of f(x) dx
- f'(b) - f'(a)
- integral from a to b of f'(x) dx
The primary application of definite integrals in this chapter is to calculate
- Derivatives of functions
- Area bounded by curves
- Determinants of matrices
- Limits of functions