myclass24
myclass24your class. your pace.
NCERT SOLUTIONS

Chapter 8-Gravitation

NCERT Solutions Class 11 Physics Chapter 8 Gravitation FAQs with detailed answers covering gravity, satellites, escape velocity and important concepts.

read this first

NCERT Solutions for Class 11 Physics Chapter 8 – Gravitation

Chapter 8 of Class 11 Physics, Gravitation, is a foundational chapter that explains one of the four fundamental forces of nature — gravity. Students explore how every object in the universe attracts every other object with a force that depends on their masses and the distance between them, as described by Newton's Law of Universal Gravitation. The chapter begins with a historical account of Kepler's three laws of planetary motion, which laid the groundwork for Newton's gravitational theory. Students learn to calculate gravitational force, gravitational potential energy, and the conditions under which objects achieve orbital or escape velocity. The variation of gravitational acceleration with altitude and depth is a commonly tested concept in board exams and entrance tests like JEE and NEET. Topics such as geo-stationary satellites, energy of a satellite in orbit, and weightlessness are explained with clear derivations. Mastery of this chapter helps students understand not just terrestrial mechanics but also celestial phenomena like tides, planetary motion, and satellite communication. The NCERT solutions provided here follow the CBSE curriculum and offer step-by-step answers to all textbook exercises, making revision efficient and conceptually sound.

NCERT Solutions PDF – Class 11 Physics Chapter 8 (All Exercises)

The PDF covers solutions to all exercises from the NCERT textbook including Exercise 8.1 to 8.33 (numericals and theory questions). Prepared by expert physics teachers as per the latest CBSE syllabus.
 

Resource NameDescriptionBest For
NCERT SolutionsDetailed answers and explanations for NCERT textbook questions across all classes and subjects.Homework, assignments, and exam preparation
NCERT Solutions for Class 11Chapter-wise solutions for all Class 11 subjects including Physics, Chemistry, Mathematics, Biology, and English.Class 11 board exam preparation
NCERT Solutions for Class 11 PhysicsStep-by-step solutions covering all chapters such as Motion, Laws of Motion, Work Energy and Power, Thermodynamics, and Waves.Concept building and numerical problem-solving
NCERT Exemplar Class 11 PhysicsAdvanced and application-based questions designed to strengthen conceptual understanding and analytical skills.JEE, NEET, Olympiads, and higher-order practice
Physics FormulaChapter-wise collection of important formulas, equations, and derivations for quick revision.Last-minute revision and numerical practice


 

Important Formulas – Chapter 8: Gravitation

FormulaExpressionDescription
Newton's Law of GravitationF = G·M·m / r²Force between two masses M and m separated by distance r; G = 6.674 × 10⁻¹¹ N m² kg⁻²
Acceleration due to gravityg = GM / R²g on Earth's surface; R = radius of Earth
g at height hg_h = g(1 − 2h/R) for h ≪ RApproximate formula; decreases with altitude
g at depth dg_d = g(1 − d/R)Decreases linearly with depth; zero at center
Gravitational Potential EnergyU = −GMm / rNegative sign indicates bound system
Orbital Velocityv_o = √(GM/r) = √(gR²/r)Speed needed for circular orbit at distance r from center
Escape Velocityv_e = √(2GM/R) = √(2gR)Minimum speed to escape Earth's gravity (≈11.2 km/s)
Time Period of SatelliteT = 2π√(r³/GM)Kepler's Third Law applied to satellites
Energy of SatelliteE = −GMm / 2rTotal mechanical energy (KE + PE) in orbit
Kepler's Third LawT² ∝ a³Square of period proportional to cube of semi-major axis
Gravitational PotentialV = −GM / rPotential energy per unit mass

Subtopics Explained – Chapter 8: Gravitation

Kepler's Laws of Planetary Motion

Kepler formulated three empirical laws based on Tycho Brahe's astronomical data. The Law of Orbits states all planets move in elliptical orbits with the Sun at one focus. The Law of Areas states the line joining a planet to the Sun sweeps equal areas in equal time intervals (conservation of angular momentum). The Law of Periods states T² ∝ a³, where a is the semi-major axis — a key formula in numerical problems.

Newton's Law of Gravitation & The Gravitational Constant

Newton generalised Kepler's findings into a universal law: every particle attracts every other with force F = GMm/r². The constant G was first measured by Cavendish using the torsion balance experiment. This law is universal — it applies from apples falling to galaxies colliding.

Acceleration Due to Gravity and Its Variation

The value of g (≈9.8 m/s²) is not constant — it varies with altitude, depth, latitude (due to Earth's rotation and shape), and even the density of local terrain. These variations are crucial for exam-oriented numerical problems.

Gravitational Potential Energy and Potential

Gravitational PE (U = −GMm/r) is always negative, signifying a bound state. Work must be done against gravity to move a mass from r to infinity. Gravitational potential V = U/m = −GM/r is the PE per unit mass.

Escape Speed and Orbital Velocity

Escape velocity is the minimum speed for an object to permanently leave a gravitational field — approximately 11.2 km/s for Earth. Orbital velocity (~7.9 km/s for near-Earth orbit) is the speed for a circular orbit; v_e = √2 × v_o.

Satellites – Geostationary and Polar

A geostationary satellite has T = 24 hours and orbits at ~36,000 km above equator, appearing stationary. Polar satellites orbit at lower altitudes (~500–800 km) and cover the entire Earth surface for remote sensing and weather monitoring.

Quick Reference Table – Key Values in Gravitation

QuantityValue / FormulaRemark
G (Gravitational Constant)6.674 × 10⁻¹¹ N m² kg⁻²Universal constant (Cavendish experiment)
Mass of Earth (M)5.97 × 10²⁴ kgStandard value
Radius of Earth (R)6.4 × 10⁶ mMean radius
g (surface)9.8 m/s²Standard value at sea level
Escape velocity (Earth)11.2 km/sMinimum to escape Earth
Orbital velocity (near Earth)~7.9 km/sFor orbit at R
Geostationary orbit altitude~35,786 kmAbove equator; T = 24 h
Relationshipv_e = √2 · v_oAlways true at same r
Energy in orbitKE = |Total Energy|KE = GMm/2r, PE = −GMm/r
WeightlessnessApparent weight = 0In free fall or orbital motion

NCERT Solutions for Class 11 Physics Chapter 8: Gravitation