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NCERT SOLUTIONS

Chapter 14-Oscillations

Access NCERT Solutions for Class 11 Physics Chapter 14 Oscillations with step-by-step answers, formulas, solved numericals, and concept-based explanations.

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NCERT Solutions for Class 11 Physics Chapter 14 – Oscillations

Chapter 14 of Class 11 Physics, Oscillations, introduces students to repetitive, to-and-fro motion — one of the most ubiquitous phenomena in nature and technology. From the swinging of a pendulum clock to the vibrations of atoms in a crystal, oscillatory motion follows universal mathematical patterns. The chapter focuses primarily on Simple Harmonic Motion (SHM), a special type of periodic motion where the restoring force is directly proportional and opposite to displacement: F = −kx. This leads to sinusoidal motion described by x(t) = A cos(ωt + φ). Students learn to derive equations for displacement, velocity, and acceleration in SHM and compute the kinetic energy, potential energy, and total mechanical energy at any instant. Two canonical systems are studied in depth: the spring-mass system (horizontal and vertical) and the simple pendulum (for small angles). 

The chapter then extends to damped oscillations — where energy is lost due to friction or drag — and forced oscillations — where an external periodic force is applied. The critical phenomenon of resonance, when the driving frequency matches the natural frequency, explains structures collapsing, musical instruments, and MRI machines. This chapter is a favourite in JEE Advanced and forms the backbone of wave theory in Chapter 15.

SHM
Spring-Mass System
Simple Pendulum
Resonance
Damped Oscillations
Energy in SHM

NCERT Solutions PDF – Class 11 Physics Chapter 14 (All Exercises)

Download Free PDF: NCERT Solutions for Class 11 Physics Chapter 14 – Oscillations. The PDF covers step-by-step answers to all NCERT exercises on SHM, spring systems, pendulum problems, energy calculations, damped and forced oscillations. Prepared per latest CBSE syllabus.

Important Formulas – Chapter 14: Oscillations

FormulaExpressionDescription
SHM Restoring ForceF = −kxk = spring constant or effective constant; negative = restoring
Displacement in SHMx(t) = A cos(ωt + φ)A = amplitude; ω = angular frequency; φ = initial phase
Angular Frequencyω = 2π/T = 2πf = √(k/m)For spring-mass system
Velocity in SHMv = −Aω sin(ωt + φ); v_max = AωMax speed at equilibrium (x=0)
Acceleration in SHMa = −ω²x; a_max = ω²AMax acceleration at extreme positions
Time Period (Spring-Mass)T = 2π√(m/k)Independent of amplitude; m = mass, k = spring constant
Time Period (Simple Pendulum)T = 2π√(L/g)Valid for small angles (θ < 15°); independent of mass
Kinetic Energy in SHMKE = ½mω²(A²−x²)Maximum at x = 0; zero at x = ±A
Potential Energy in SHMPE = ½mω²x²= ½kx²Minimum at x = 0; maximum at x = ±A
Total EnergyE = ½mω²A² = ½kA²Constant in undamped SHM; independent of x
Velocity-displacementv = ω√(A²−x²)Useful for finding speed at any position
Damped Oscillationx = Ae^(−bt/2m) cos(ω't + φ)Amplitude decreases exponentially; ω' = √(ω²−b²/4m²)

Subtopics Explained – Chapter 14: Oscillations

Periodic and Oscillatory Motion

Periodic motion repeats after a fixed time interval (period T). Oscillatory motion is periodic motion about a fixed equilibrium position. All oscillatory motion is periodic, but not vice versa (e.g., Earth's revolution is periodic but not oscillatory). SHM is the simplest and most important type of oscillatory motion.

Simple Harmonic Motion (SHM)

SHM is defined by a linear restoring force: F = −kx. The solution is sinusoidal. At amplitude ±A, velocity is zero and acceleration is maximum. At equilibrium (x = 0), velocity is maximum (v_max = Aω) and acceleration is zero. Understanding these phase relationships is critical for solving NCERT problems efficiently.

Spring-Mass System

For a mass m on a spring of constant k, T = 2π√(m/k). For a vertical spring, the equilibrium shifts by mg/k but the time period remains the same. For springs in series, k_eff = k₁k₂/(k₁+k₂); for parallel, k_eff = k₁+k₂. These spring combinations are frequent exam topics.

Simple Pendulum

A simple pendulum (point mass on inextensible string) executes SHM for small angles, with T = 2π√(L/g). The period is independent of mass and amplitude (for small angles) — a key property. The pendulum can be used to determine g experimentally. Seconds pendulum has T = 2 s, so L ≈ 1 m for standard g.

Damped and Forced Oscillations

In damped oscillations, resistive forces reduce amplitude over time. The system is underdamped (oscillates with decreasing amplitude), critically damped (returns to equilibrium fastest without oscillation), or overdamped (slowly returns). In forced oscillations, an external periodic force is applied. When its frequency matches the system's natural frequency, resonance occurs — amplitude becomes very large, which is both useful (MRI, musical instruments) and dangerous (bridge collapses).

Resource NameDescriptionBest For
NCERT SolutionsDetailed answers and explanations for NCERT textbook questions across all classes and subjects.Homework, assignments, and exam preparation
NCERT Solutions for Class 11Chapter-wise solutions for all Class 11 subjects including Physics, Chemistry, Mathematics, Biology, and English.Class 11 board exam preparation
NCERT Solutions for Class 11 PhysicsStep-by-step solutions covering all chapters such as Motion, Laws of Motion, Work Energy and Power, Thermodynamics, and Waves.Concept building and numerical problem-solving
NCERT Exemplar Class 11 PhysicsAdvanced and application-based questions designed to strengthen conceptual understanding and analytical skills.JEE, NEET, Olympiads, and higher-order practice
Physics FormulaChapter-wise collection of important formulas, equations, and derivations for quick revision.Last-minute revision and numerical practice

Quick Reference Table – Key Comparisons in Oscillations

SystemTime PeriodDepends OnDoes NOT Depend On
Spring-Mass2π√(m/k)Mass m, spring constant kAmplitude, g
Simple Pendulum2π√(L/g)Length L, gravity gMass, amplitude (small)
Liquid in U-tube2π√(L/2g)Length of liquid column LMass, density
Torsional Pendulum2π√(I/C)Moment of inertia I, torsion CAmplitude
SHM EnergyE = ½kA²Amplitude A, spring constant kMass, position x

NCERT Solutions for Class 11 Physics Chapter 14: Oscillations – FAQs