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Chapter 10-Mechanical Properties of Fluids

NCERT Solutions Class 11 Physics Chapter 10 Fluids Chapter 10 Mechanical Properties of Fluids covering pressure, buoyancy, viscosity and Bernoulli’s Principle.

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NCERT Solutions for Class 11 Physics Chapter 10 – Mechanical Properties of Fluids

Chapter 10 of Class 11 Physics, Mechanical Properties of Fluids, explores the behaviour of liquids and gases under rest and motion. Fluids (liquids and gases) differ from solids in their ability to flow and take the shape of their container. This chapter covers both fluid statics — study of fluids at rest, including pressure, Pascal's Law, buoyancy, and Archimedes' Principle — and fluid dynamics — study of fluids in motion, through the equation of continuity and Bernoulli's theorem. Bernoulli's Principle is one of the most important and widely applied concepts in Physics, explaining the lift on aircraft wings, the working of spray guns, and the Venturi meter. Students also study viscosity, which measures a fluid's internal resistance to flow, and Stokes' Law for the terminal velocity of spheres falling through viscous media. The chapter concludes with surface tension — a surface property arising from cohesive forces — explaining capillarity, the shape of liquid drops, and the working of detergents. This chapter has direct applications in aeronautics, hydraulics, blood flow in arteries, and daily phenomena. NCERT solutions for Chapter 10 present detailed, exam-ready answers to all exercises under the latest CBSE syllabus.

NCERT Solutions PDF – Class 11 Physics Chapter 10 (All Exercises)

Download Free PDF: NCERT Solutions for Class 11 Physics Chapter 10 – Mechanical Properties of Fluids. The PDF contains step-by-step solutions to all exercises, including Pascal's Law, fluid flow, Bernoulli applications, viscosity, and surface tension problems. Aligned with the latest CBSE/NCERT curriculum.
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NCERT SolutionsDetailed answers and explanations for NCERT textbook questions across all classes and subjects.Homework, assignments, and exam preparation
NCERT Solutions for Class 11Chapter-wise solutions for all Class 11 subjects including Physics, Chemistry, Mathematics, Biology, and English.Class 11 board exam preparation
NCERT Solutions for Class 11 PhysicsStep-by-step solutions covering all chapters such as Motion, Laws of Motion, Work Energy and Power, Thermodynamics, and Waves.Concept building and numerical problem-solving
NCERT Exemplar Class 11 PhysicsAdvanced and application-based questions designed to strengthen conceptual understanding and analytical skills.JEE, NEET, Olympiads, and higher-order practice
Physics FormulaChapter-wise collection of important formulas, equations, and derivations for quick revision.Last-minute revision and numerical practice

Important Formulas – Chapter 10: Mechanical Properties of Fluids

FormulaExpressionDescription
Fluid PressureP = F / APressure = force per unit area; unit: Pascal (Pa)
Pressure at depth hP = P₀ + ρghP₀ = atmospheric pressure; ρ = fluid density
Pascal's LawΔP transmitted equallyPressure change in enclosed fluid is transmitted uniformly
Archimedes' PrincipleF_b = ρ_fluid · V_sub · gBuoyant force = weight of displaced fluid
Equation of ContinuityA₁v₁ = A₂v₂Conservation of mass in steady flow
Bernoulli's EquationP + ½ρv² + ρgh = constantConservation of energy in ideal fluid flow
Torricelli's Theoremv = √(2gh)Speed of efflux from a hole at depth h below free surface
Viscous Force (Stokes' Law)F = 6πηrvη = viscosity, r = sphere radius, v = velocity
Terminal Velocityv_t = 2r²(ρ−σ)g / 9ηρ = sphere density, σ = fluid density
Reynolds NumberRe = ρvD / ηRe < 1000: laminar; Re > 2000: turbulent
Surface TensionT = F / LForce per unit length on a liquid surface; unit: N/m
Excess Pressure (bubble)ΔP = 4T/r (soap); 2T/r (liquid drop)Soap bubble has 2 surfaces; liquid drop has 1
Capillary Riseh = 2T cosθ / (rρg)θ = contact angle; r = tube radius

Subtopics Explained – Chapter 10: Mechanical Properties of Fluids

Fluid Pressure and Pascal's Law

Pressure in a static fluid increases with depth as P = P₀ + ρgh. Pascal's Law states that any pressure applied to an enclosed fluid is transmitted equally and undiminished in all directions. This principle underlies hydraulic lifts, car brakes, and hydraulic presses — all high-value real-life applications in NCERT problems.

Archimedes' Principle and Buoyancy

A body immersed in a fluid experiences an upward buoyant force equal to the weight of the displaced fluid. This explains why ships float, submarines dive, and hot air balloons rise. The condition for floating is that buoyant force ≥ weight of the object.

Bernoulli's Theorem and Applications

For steady, incompressible, non-viscous flow, the sum P + ½ρv² + ρgh remains constant along a streamline. Applications include: lift on aircraft wings (Venturi effect), Pitot tube, spray atomisers, and the Venturi meter. This is one of the most conceptually rich and exam-important topics in the chapter.

Viscosity and Stokes' Law

Viscosity is a measure of a fluid's resistance to flow. Honey is more viscous than water. The viscous drag force on a sphere is given by Stokes' Law: F = 6πηrv. At terminal velocity, this drag force plus buoyancy exactly balances gravity, so the sphere moves at constant speed.

Surface Tension and Capillarity

Surface tension arises from cohesive forces between liquid molecules at the surface. It causes soap bubbles, water droplets, and insects walking on water. Capillary rise (or depression) is observed in narrow tubes — water rises in glass (contact angle < 90°) while mercury is depressed (contact angle > 90°). Detergents work by reducing surface tension.

Quick Reference Table – Important Values and Comparisons

ConceptKey DetailApplication
Atmospheric Pressure1.013 × 10⁵ Pa = 76 cm HgBarometer, weather systems
Density of water1000 kg/m³ at 4°CBuoyancy calculations
Viscosity of water (20°C)~1 × 10⁻³ Pa·sStokes' Law problems
Surface tension of water0.073 N/m at 20°CCapillarity, drops, bubbles
Bernoulli vs TorricelliTorricelli is a special case of BernoulliTank drainage problems
Laminar vs TurbulentRe <1000 → laminar; Re >2000 → turbulentPipe flow design
Continuity EquationAv = constant for incompressible flowNozzles, arterial blood flow
Soap Bubble PressureΔP = 4T/r (two surfaces)Why smaller bubbles have higher pressure

NCERT Solutions for Class 11 Physics Chapter 10: Mechanical Properties of Fluids