myclass24
myclass24your class. your pace.
NCERT SOLUTIONS

Chapter 9-Sequences and Series

Access NCERT Solutions for Class 11 Maths Chapter 9 Sequences and Series with solved exercises, formulas, examples

read this first

NCERT Solutions for Class 11 Maths Chapter 9 – Sequences and Series

Subject: Mathematics | Class: 11 | Chapter: 9 | Board: CBSE | Curriculum: New NCERT

What Are NCERT Solutions for Class 11 Maths Chapter 9 – Sequences and Series?

Numbers rarely exist alone in mathematics. They appear in patterns — a salary that increases by a fixed amount each year, a bouncing ball that covers half the previous height with each bounce, the way bacteria double every hour. These patterns have a name in mathematics: sequences. And when you add the terms of a sequence together, you get a series. Chapter 9 of NCERT solutions Class 11 Mathematics is dedicated to studying these patterns with precision. For all Chapters must, read NCERT Solutions for Class 11 Maths and subject-wise NCERT Solutions for Class 11

NCERT structures this chapter around three main types of sequences: Arithmetic Progressions (AP), Geometric Progressions (GP), and a brief but important introduction to Arithmetic-Geometric Progressions and special series. You have encountered AP and GP at the Class 10 level, but Chapter 9 takes both considerably deeper. The nth term, sum formulas, properties, insertion of means, and relationship between AP and GP are all developed here with more rigor and more complex applications.

What students often underestimate is how many different question types emerge from just these two progression types. A single GP problem might require you to find the number of terms, identify the common ratio from a condition on the sum, and verify a property — all in one question. These solutions are built to show every step of that reasoning, using NCERT's own notation, so that your answers in CBSE match what the examiner expects to see. The chapter carries a consistent presence in both board exams and competitive tests, making it one of the highest-return chapters to master in this course.

Download PDF – All Exercises of NCERT Solutions for Class 11 Maths Chapter 9 Sequences and Series

📄 Exercise-9.1
📄 Exercise-9.2
📄 Exercise-9.3
📄 Exercise-9.4
📄 Miscellaneous
ExerciseTopic CoveredNumber of Questions
Exercise 9.1Sequences – nth Term, Types, Basic Problems14 Questions
Exercise 9.2Arithmetic Progressions – nth Term, Sum18 Questions
Exercise 9.3Geometric Progressions – nth Term, Sum, Infinite GP32 Questions
Exercise 9.4Special Series – Sum of n, n², n³10 Questions
MiscellaneousMixed AP, GP, AGP Problems32 Questions

Chapter 9 – Sequences and Series: Concepts, Explanation and Key Tables

Arithmetic Progression (AP) — The Constant Difference Sequence

An Arithmetic Progression is a sequence where the difference between any two consecutive terms is always the same. This fixed difference is called the common difference, denoted d. The first term is denoted a.

If a sequence is a₁, a₂, a₃, ..., then it is an AP if and only if a₂ – a₁ = a₃ – a₂ = d (constant).

All Formulas for Arithmetic Progression

FormulaExpressionWhen to Use
nth term (general term)aₙ = a + (n–1)dFinding any specific term given a and d
Sum of n termsSₙ = n/2 × [2a + (n–1)d]When first term and common difference are known
Sum using first and last termSₙ = n/2 × (a + l)When first term a and last term l are known
Common differenced = (aₙ – a) / (n–1)Finding d when nth term and first term are given
Arithmetic Mean of two numbersAM = (a + b) / 2Mean inserted between two numbers
n Arithmetic Means between a and bd = (b – a) / (n+1)Inserting n means between a and b
Three terms in APTake as a–d, a, a+dSimplifies sum and product conditions
Four terms in APTake as a–3d, a–d, a+d, a+3dUse when product or sum given

Geometric Progression (GP) — The Constant Ratio Sequence

A Geometric Progression is a sequence where the ratio of any term to the term before it is always the same. This fixed ratio is called the common ratio, denoted r.

If a sequence is a₁, a₂, a₃, ..., then it is a GP if and only if a₂/a₁ = a₃/a₂ = r (constant).

All Formulas for Geometric Progression

FormulaExpressionCondition / Notes
nth termaₙ = arⁿ⁻¹a = first term, r = common ratio
Sum of n terms (r ≠ 1)Sₙ = a(rⁿ – 1)/(r – 1)Use when r > 1 for cleaner form
Sum of n terms (r < 1)Sₙ = a(1 – rⁿ)/(1 – r)Use when r < 1 to keep denominator positive
Sum of n terms (r = 1)Sₙ = naAll terms equal; simply multiply by n
Sum of infinite GPS∞ = a/(1 – r)Only valid when
Geometric Mean of two numbersGM = √(ab)For positive a and b
n Geometric Means between a and br = (b/a)^[1/(n+1)]Common ratio for inserting n means
Three terms in GPTake as a/r, a, arSimplifies product condition elegantly
Relationship AM ≥ GMFor positive reals: (a+b)/2 ≥ √(ab)Equality when a = b

AP vs GP — Side by Side Comparison

FeatureArithmetic Progression (AP)Geometric Progression (GP)
Defining propertyConstant difference: d = aₙ₊₁ – aₙConstant ratio: r = aₙ₊₁ / aₙ
General terma + (n–1)darⁿ⁻¹
Sum of n termsn/2[2a + (n–1)d]a(rⁿ–1)/(r–1)
Middle term propertyMiddle term = AM of first and lastMiddle term = GM of first and last
When sum is givenUse Sₙ – Sₙ₋₁ = aₙCannot directly apply; use Sₙ formula
Infinite sumDiverges (unless d = 0)Converges to a/(1–r) when
Graph shapeStraight lineExponential curve

Special Series Formulas (Exercise 9.4)

SeriesFormula
Sum of first n natural numbers1 + 2 + 3 + ... + n = n(n+1)/2
Sum of squares of first n naturals1² + 2² + 3² + ... + n² = n(n+1)(2n+1)/6
Sum of cubes of first n naturals1³ + 2³ + 3³ + ... + n³ = [n(n+1)/2]²
Sum of first n odd numbers1 + 3 + 5 + ... + (2n–1) = n²
Sum of first n even numbers2 + 4 + 6 + ... + 2n = n(n+1)

Inserting Means Between Two Numbers

TypeBetween a and bFormula for each mean
Single AMArithmetic MeanAM = (a + b)/2
Single GMGeometric MeanGM = √(ab), for a, b > 0
Single HMHarmonic MeanHM = 2ab/(a + b)
n AMsInsert n arithmetic meansd = (b–a)/(n+1); means = a+d, a+2d, ..., a+nd
n GMsInsert n geometric meansr = (b/a)^[1/(n+1)]; means = ar, ar², ..., arⁿ

Study Tips for Chapter 9

  • For three terms in AP, always assume them as (a–d), a, (a+d). Their sum is 3a — which instantly gives you a when the sum is provided, making the problem half-solved.
  • Similarly, for three terms in GP, assume a/r, a, ar. Their product is a³ — divide both sides by the product given and you find a immediately.
  • Infinite GP convergence (|r| < 1) must be verified before applying S∞ = a/(1–r) — write this check explicitly in board answers.
  • The Miscellaneous Exercise in this chapter is long and diverse. Practise at least 15 problems from it to cover the variety of application types.

FAQs on NCERT Solutions Class 11 Maths Chapter 9 Sequences and Series