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NCERT SOLUTIONS

Chapter 10-Straight Lines

Get NCERT Solutions for Class 11 Maths Chapter 10 Straight Lines with solved exercises, formulas, coordinate geometry concepts

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NCERT Solutions for Class 11 Maths Chapter 10 – Straight Lines

Subject: Mathematics | Class: 11 | Chapter: 10 | Board: CBSE | Curriculum: New NCERT

What Are NCERT Solutions for Class 11 Maths Chapter 10 – Straight Lines?

A line is perhaps the simplest geometric object, yet the algebraic machinery built around it in Chapter 10 is rich enough to describe almost anything that is linear in two dimensions. If you have studied coordinate geometry in Class 9 and 10, you already know the slope-intercept form and the distance formula. Chapter 10 takes these ideas and builds a complete, systematic theory of straight lines — including five different forms of the equation of a line, the angle between two lines, distance of a point from a line, and the family of lines passing through the intersection of two given lines. For all Chapters must, read NCERT Solutions for Class 11 Maths and subject-wise NCERT Solutions for Class 11

What makes this chapter feel significant is its role as the bridge between pure geometry and algebra. Every geometric property of a line — its inclination, its perpendicularity with another line, how far it is from a point — gets translated into an algebraic condition. This translation skill is what Chapter 10 develops.

NCERT's structure here is logical: first define slope, then build up the five forms of a line one by one, then explore relationships between lines (parallel, perpendicular, angle between them), and finally solve distance and intersection problems. The solutions here show all five forms and when to use each, because one of the most common errors in CBSE answers is using the wrong form and then spending time converting — a step that can often be avoided entirely by choosing the right starting form.

Download PDF – All Exercises of NCERT Solutions for Class 11 Maths Chapter 10 Straight Line

📄 Exercise-10.1
📄 Exercise-10.2
📄 Exercise-10.3
📄 Miscellaneous
ExerciseTopic CoveredNumber of Questions
Exercise 10.1Slope of a Line; Collinearity; Angle of Inclination14 Questions
Exercise 10.2Five Forms of Equation of a Line20 Questions
Exercise 10.3General Form; Distance of Point from Line; Intersection18 Questions
MiscellaneousMixed Problems, Families of Lines24 Questions

Chapter 10 – Straight Lines: Concepts, Explanation and Key Tables

Slope and Angle of Inclination

The slope (or gradient) of a line measures how steeply it rises or falls. If a line makes an angle θ with the positive direction of the x-axis (measured anticlockwise), then:

m = tan θ

For a line passing through two points (x₁, y₁) and (x₂, y₂):

m = (y₂ – y₁) / (x₂ – x₁)

A horizontal line has slope 0. A vertical line has an undefined slope.

Five Forms of the Equation of a Straight Line

This is the heart of Exercise 10.2 and the most tested part of this chapter:

FormEquationWhen to UseGiven Information
Slope-Intercept Formy = mx + cWhen slope and y-intercept are knownm and c
Point-Slope Formy – y₁ = m(x – x₁)When slope and one point are knownm and (x₁, y₁)
Two-Point Form(y – y₁)/(y₂ – y₁) = (x – x₁)/(x₂ – x₁)When two points on the line are known(x₁,y₁) and (x₂,y₂)
Intercept Formx/a + y/b = 1When x-intercept (a) and y-intercept (b) are knowna ≠ 0, b ≠ 0
Normal Formx cos ω + y sin ω = pWhen perpendicular distance from origin and angle of normal are knownp > 0, ω ∈ [0, 2π)

Parallel and Perpendicular Lines

ConditionRelationshipSlope Condition
Lines are parallelSame direction, never meetm₁ = m₂
Lines are perpendicularMeet at 90°m₁ × m₂ = –1
Lines are identical (coincident)Same linem₁ = m₂ and same intercept
Lines are neither parallel nor perpendicularIntersect at some anglem₁ ≠ m₂ and m₁m₂ ≠ –1

Angle Between Two Lines

If θ is the acute angle between two lines with slopes m₁ and m₂, then:

tan θ = |(m₁ – m₂) / (1 + m₁m₂)|

If 1 + m₁m₂ = 0, the lines are perpendicular and θ = 90°.

Key Distance and Position Formulas

FormulaExpressionUse
Distance of point (x₁, y₁) from line ax + by + c = 0d =ax₁ + by₁ + c
Distance between two parallel lines ax+by+c₁=0 and ax+by+c₂=0d =c₁ – c₂
Foot of perpendicular from (x₁,y₁) to line ax+by+c=0Use parametric intersectionLess common but appears in miscellaneous
Point of intersection of two linesSolve simultaneouslyAlways get two equations, two unknowns

Collinearity of Three Points

Three points A, B, C are collinear (lie on the same line) if and only if:

Slope of AB = Slope of BC

Equivalently, the area of the triangle formed by three points = 0: Area = ½ |x₁(y₂ – y₃) + x₂(y₃ – y₁) + x₃(y₁ – y₂)| = 0

Reducing General Form to Standard Forms

The general equation of a line is ax + by + c = 0. From this you can extract:

QuantityHow to Get It from ax + by + c = 0
Slopem = –a/b (when b ≠ 0)
x-interceptSet y = 0: x = –c/a
y-interceptSet x = 0: y = –c/b
Distance from origind =
Normal formDivide entire equation by √(a² + b²); adjust signs so RHS > 0

Study Tips for Chapter 10

  • Before writing the equation of a line in CBSE, identify which form is most natural given the data in the question. Using the wrong form means extra conversion steps.
  • For distance formula problems, always convert the line to the form ax + by + c = 0 first — working with y = mx + c in the distance formula leads to errors.
  • The family of lines through the intersection of L₁ and L₂ is written as L₁ + λL₂ = 0 — this elegant technique appears in the miscellaneous exercise and is worth understanding conceptually.
  • Collinearity and area questions are often combined with other topics — practise treating them as sub-problems within larger questions.

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