MyClass24 logo
myclass24
YOUR CLASS. YOUR PACE.
A
Aditi Singh
·23 March 2026

Complete Trigonometry Formulas: All Important Formulas for Class 10, 11 & 12

Why it matters:

Every competitive exam (JEE, NEET, SAT) tests trigonometry heavily. Mastering these formulas gives you a solid foundation.

How to use it:

Understand the basic ratios first, then move to identities and transformations.

Basic Trigonometry Ratios

These are the foundation of all trigonometry. In a right-angled triangle:

RatioFormulaExplanationVariables
Sinesin θ = Opposite/HypotenuseRatio of opposite side to hypotenuseθ = angle
Cosinecos θ = Adjacent/HypotenuseRatio of adjacent side to hypotenuseθ = angle
Tangenttan θ = Opposite/AdjacentRatio of opposite to adjacent sideθ = angle
Cosecantcosec θ = Hypotenuse/OppositeReciprocal of sineθ = angle
Secantsec θ = Hypotenuse/AdjacentReciprocal of cosineθ = angle
Cotangentcot θ = Adjacent/OppositeReciprocal of tangentθ = angle

Memory Trick: SOHCAHTOA

  • Sin = Opposite/Hypotenuse
  • Cos = Adjacent/Hypotenuse
  • Tan = Opposite/Adjacent

Trigonometry Table (Standard Angles)

This table is gold for exams. Memorize it.

Angle (θ)30°45°60°90°
sin θ01/21/√2√3/21
cos θ1√3/21/√21/20
tan θ01/√31√3
cosec θ2√22/√31
sec θ12/√3√22
cot θ√311/√30

Pattern for sin θ: √0/2, √1/2, √2/2, √3/2, √4/2

Pattern for cos θ: Reverse of sin (√4/2, √3/2, √2/2, √1/2, √0/2)

Reciprocal Identities

Formula NameFormulaExplanation
Cosecantcosec θ = 1/sin θReciprocal of sine
Secantsec θ = 1/cos θReciprocal of cosine
Cotangentcot θ = 1/tan θReciprocal of tangent
Alternative tantan θ = sin θ/cos θTangent as ratio of sin and cos
Alternative cotcot θ = cos θ/sin θCotangent as ratio of cos and sin

Pythagorean Identities

These come directly from the Pythagorean theorem.

FormulaExplanationUse Case
sin²θ + cos²θ = 1Most fundamental identitySimplifying expressions
1 + tan²θ = sec²θDerived by dividing first identity by cos²θSolving sec, tan problems
1 + cot²θ = cosec²θDerived by dividing first identity by sin²θSolving cosec, cot problems

Example: If sin θ = 3/5, find cos θ.

Using sin²θ + cos²θ = 1:

  • (3/5)² + cos²θ = 1
  • 9/25 + cos²θ = 1
  • cos²θ = 16/25
  • cos θ = 4/5

Trigonometric Ratios of Complementary Angles

Complementary angles add up to 90°.

FormulaExplanation
sin(90° - θ) = cos θSine becomes cosine
cos(90° - θ) = sin θCosine becomes sine
tan(90° - θ) = cot θTangent becomes cotangent
cot(90° - θ) = tan θCotangent becomes tangent
sec(90° - θ) = cosec θSecant becomes cosecant
cosec(90° - θ) = sec θCosecant becomes secant

Memory Trick: Co-function of (90° - θ) = function of θ

Sum and Difference Formulas

These help you find trigonometric values of sum or difference of two angles.

Formula NameFormula
sin(A + B)sin A cos B + cos A sin B
sin(A - B)sin A cos B - cos A sin B
cos(A + B)cos A cos B - sin A sin B
cos(A - B)cos A cos B + sin A sin B
tan(A + B)(tan A + tan B)/(1 - tan A tan B)
tan(A - B)(tan A - tan B)/(1 + tan A tan B)

Example: Find sin 75°.

sin 75° = sin(45° + 30°) = sin 45° cos 30° + cos 45° sin 30° = (1/√2)(√3/2) + (1/√2)(1/2) = (√3 + 1)/2√2

Double Angle Formulas

Used when angle is doubled.

Formula NameFormulaAlternative Forms
sin 2θ2 sin θ cos θ
cos 2θcos²θ - sin²θ2cos²θ - 1 or 1 - 2sin²θ
tan 2θ2tan θ/(1 - tan²θ)

Example: If sin θ = 3/5, find sin 2θ.

sin 2θ = 2 sin θ cos θ = 2(3/5)(4/5) = 24/25

Triple Angle Formulas

For Class 11 and 12 advanced problems.

FormulaExpression
sin 3θ3sin θ - 4sin³θ
cos 3θ4cos³θ - 3cos θ
tan 3θ(3tan θ - tan³θ)/(1 - 3tan²θ)

Half Angle Formulas

FormulaExpression
sin θ/2±√[(1 - cos θ)/2]
cos θ/2±√[(1 + cos θ)/2]
tan θ/2±√[(1 - cos θ)/(1 + cos θ)] or sin θ/(1 + cos θ)

The sign depends on which quadrant θ/2 lies in.

Product-to-Sum Formulas

Convert products into sums for easier integration and simplification.

FormulaExpression
sin A sin B[cos(A - B) - cos(A + B)]/2
cos A cos B[cos(A - B) + cos(A + B)]/2
sin A cos B[sin(A + B) + sin(A - B)]/2
cos A sin B[sin(A + B) - sin(A - B)]/2

Sum-to-Product Formulas

Convert sums into products.

FormulaExpression
sin A + sin B2 sin[(A + B)/2] cos[(A - B)/2]
sin A - sin B2 cos[(A + B)/2] sin[(A - B)/2]
cos A + cos B2 cos[(A + B)/2] cos[(A - B)/2]
cos A - cos B-2 sin[(A + B)/2] sin[(A - B)/2]

Inverse Trigonometry Formulas

Basic Inverse Trigonometric Functions

FunctionDomainRange
sin⁻¹x[-1, 1][-π/2, π/2]
cos⁻¹x[-1, 1][0, π]
tan⁻¹x(-∞, ∞)(-π/2, π/2)
cosec⁻¹x(-∞, -1] ∪ [1, ∞)[-π/2, 0) ∪ (0, π/2]
sec⁻¹x(-∞, -1] ∪ [1, ∞)[0, π/2) ∪ (π/2, π]
cot⁻¹x(-∞, ∞)(0, π)

Important Inverse Trigonometry Properties

PropertyFormula
sin⁻¹(-x)-sin⁻¹x
cos⁻¹(-x)π - cos⁻¹x
tan⁻¹(-x)-tan⁻¹x
sin⁻¹x + cos⁻¹xπ/2
tan⁻¹x + cot⁻¹xπ/2
sec⁻¹x + cosec⁻¹xπ/2
tan⁻¹x + tan⁻¹ytan⁻¹[(x + y)/(1 - xy)]
tan⁻¹x - tan⁻¹ytan⁻¹[(x - y)/(1 + xy)]
2tan⁻¹xsin⁻¹[2x/(1 + x²)] or cos⁻¹[(1 - x²)/(1 + x²)]

Solved Examples

Example 1: Using Pythagorean Identity

Problem: If tan θ = 3/4, find sec θ.

Solution: Using 1 + tan²θ = sec²θ

  • 1 + (3/4)² = sec²θ
  • 1 + 9/16 = sec²θ
  • 25/16 = sec²θ
  • sec θ = 5/4

Example 2: Sum Formula Application

Problem: Find the value of sin 15°.

Solution: sin 15° = sin(45° - 30°) = sin 45° cos 30° - cos 45° sin 30° = (1/√2)(√3/2) - (1/√2)(1/2) = (√3 - 1)/2√2

Example 3: Inverse Trigonometry

Problem: Simplify tan⁻¹(1) + cos⁻¹(1/2)

Solution: tan⁻¹(1) = π/4 (since tan π/4 = 1) cos⁻¹(1/2) = π/3 (since cos π/3 = 1/2) Answer = π/4 + π/3 = 7π/12

Common Mistakes to Avoid

Mistake 1: Confusing sin²θ with sin(θ²)

  • sin²θ means (sin θ)², not sin of θ squared

Mistake 2: Forgetting domain restrictions in inverse functions

  • sin⁻¹(2) is undefined because sin x can never equal 2

Mistake 3: Using degree mode when answer needs radians (or vice versa)

  • Always check calculator settings

Mistake 4: Mixing up complementary angle formulas

  • sin(90° - θ) = cos θ, not sin θ

Mistake 5: Wrong signs in sum/difference formulas

  • cos(A + B) has a minus: cos A cos B - sin A sin B

Tips & Memory Tricks for Students

For Standard Angles:

  • Use the √0, √1, √2, √3, √4 pattern divided by 2 for sin
  • Reverse it for cos

For Complementary Angles:

  • "Co" functions swap at 90°
  • sin ↔ cos, tan ↔ cot, sec ↔ cosec

For Sum Formulas:

  • sin keeps order: sin A cos B + cos A sin B
  • cos swaps and changes sign: cos A cos B - sin A sin B

For Pythagorean Identities:

  • Remember sin²θ + cos²θ = 1 first
  • Divide by cos²θ to get tan/sec form
  • Divide by sin²θ to get cot/cosec form

Frequently Asked Questions about Trigonometry Formula

Q. What are the 6 basic trigonometry formulas?

The six basic ratios are sin θ, cos θ, tan θ, cosec θ, sec θ, and cot θ. Use SOHCAHTOA to remember: sin = opposite/hypotenuse, cos = adjacent/hypotenuse, tan = opposite/adjacent. The other three are their reciprocals.

Q. How do I memorize the trigonometry table quickly?

Use the √n/2 pattern for sin values (n = 0,1,2,3,4), then reverse for cos. Write it 5 times daily for 3 days. Test yourself without looking. Repetition builds memory faster than staring at the table.

Q. What's the difference between sin⁻¹x and 1/sin x?

sin⁻¹x (or arcsin x) is the inverse function that gives you an angle. 1/sin x is cosec x, the reciprocal ratio. They're completely different. sin⁻¹(1/2) = 30°, but 1/sin(30°) = 2.

Q. Which trigonometry formulas are most important for Class 10?

Focus on basic ratios, standard angle values, Pythagorean identities (sin²θ + cos²θ = 1), and complementary angle formulas. Class 10 rarely goes beyond these basics, so master them thoroughly before moving on.

Q. How do I know which formula to use in a problem?

Look at what's given and what's asked. If you have one function and need another, use identities. If you have two angles, use sum formulas. Practice identifying patterns in problems.

Q. Are inverse trigonometry formulas hard to learn?

Not if you know their domains and ranges first. Remember that sin⁻¹x + cos⁻¹x = π/2 and tan⁻¹x + cot⁻¹x = π/2. These two properties solve 60% of inverse trig problems in Class 12 exams.

Q. Can I use these formulas in competitive exams like JEE?

Absolutely. JEE tests trigonometry heavily. You need all these formulas plus their applications in calculus and coordinate geometry. Make a formula sheet and revise it weekly. Speed and accuracy both matter in JEE.

Q. What's the best way to practice trigonometry?

Solve 5 problems daily using different formula types. Mix basic problems with challenging ones. Time yourself. Teach concepts to a friend. Active problem-solving builds mastery faster than passive reading ever will.

Trigonometry isn't about memorizing random formulas. It's about understanding patterns and relationships. Once you see how each formula connects to the others how Pythagorean identities lead to double angles, how complementary angles simplify complex problems it all starts making sense.

Complete Trigonometry Formulas: All Important Formulas for Class 10, 11 & 12