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MathematicsClass 6CBSE

Find the product of the greatest 3-digit number and the greatest 2-digit number.

Greatest 3-digit number = 999Greatest 2-digit number = 99∴ Product = 999 × 99 = 999 × (100 – 1)= 999 × 100 – 999 × 1= 99900 – 999 = 98901

MathematicsClass 6CBSE

A dealer purchased 124 LED sets. If the cost of one set is ₹38,540, determine their total cost.

Total cost of 124 LED sets = ₹(38,540 × 124)= ₹ [38,540 × (100 + 20 + 4)]= ₹ [38,540 × 100 + 38,540 × 20 + 38,540 × 4]= ₹ [38,54,000 + 7,70,800 + 1,54,160]= ₹ 47,789,6

MathematicsClass 6CBSE

Give one example for each of the following properties for whole numbers.(a) Closure property(b) Commutative property(c) Associative property(d) Distributive property

(a) 3 + 4 = 7 (whole number) closure property(b) 4 + 5 = 5 + 4 Commutative property(c) 3 + (5 + 7) = (3 + 5) + 7 Associative property(d) 6 × (8 + 3) = 6 × 8 + 6 × 3 Distributive property.

MathematicsClass 6CBSE

Represent the following on number line:(a) 3 + 4(b) 6 – 2(c) 2 × 4

(a) 3 + 4(b) 6 – 2(c) 2 x 4

MathematicsClass 6CBSE

Using the properties of whole numbers, find the value of the following in suitable way:(a) 945 × 4 × 25(b) 40 × 328 × 25

(a) 945 × 4 × 25 = 945 × (4 × 25)= 945 × 100 = 94500(b) 40 × 328 × 25 = 328 × (40 × 25)= 328 × 1000 = 328000

MathematicsClass 6CBSE

Observe the following patterns and extend them by two more terms.

Next two terms are1010101 × 1010101= 1020304030201101010101 × 101010101=10203040504030201

MathematicsClass 6CBSE

Using the properties, find the values of each of the following:(a) 736 × 102(b) 8165 × 169 – 8165 × 69

(a) 736 × 102 = 736 × (100 + 2)= 736 × 100 + 736 × 2 [Using distributive property]= 73600 + 1472 = 75072(b) 8165 × 169 – 8165 × 69 = 8165 × (169 – 69) [Using distributive property]= 8165 × 100 = 816500

MathematicsClass 6CBSE

For n = 5, verify the given statement 10 × n + 1 = n1

Given statement is10 x n + 1 = n1Put n = 5, 10 x 5 + 1 = 51⇒ 50 + 1 = 51⇒ 51 = 51. Hence, verified.

MathematicsClass 6CBSE

Write the predecessor of the smallest 4-digit number.

The smallest 4-digit number = 1000∴ The predecessor of 1000 = 1000 – 1 = 999

MathematicsClass 6CBSE

Find the product of the greatest 3-digit number and the smallest 2-digit number.

The greatest 3-digit number = 999The smallest 2-digit number = 10∴ Product = 999 x 10 = 9990

MathematicsClass 6CBSE

Using distributive property, solve the following:(а) 360 × 102(b) 35 × 98

(a) 36 × 102 = 36 × (100 + 2)= 36 × 100 + 36 × 2= -36000 + 72 = 36072(b) 35 × 98 = 35 × (100 – 2) = 35 × 100 – 35 × 2= 3500 – 70 = 3430

MathematicsClass 6CBSE

Add the following in three ways. Indicate the property used.(a) 25 + 36 + 15(b) 30 + 18 + 22

(a) 25 + 36 + 15Way I: 25 + (36 + 15) = 25 + 51 = 76Way II: (25 + 36) + 15 = 61 + 15 = 76Way III: (25 + 15) + 36 = 40 + 36 = 76Here, we have used associative property.(b) 30 + 18 + 22Way I: 30 + (18 + 22) = 30 + 40 = 70Way II: (30 + 18) + 22 = 48 + 22 = 70Way III: (30 + 22) + 18 = 52 + 18 = 70Here, we have used associative property.

MathematicsClass 6CBSE

Which property do the following statements hold?(a) 6 + 4 = 4 + 6(b) 3 + 2 = whole number

(a) 6 + 4 = 4 + 6 holds commutative property of addition.(b) 3 + 2 = whole number holds closure property.

MathematicsClass 6CBSE

What is the predecessor of whole number 0?

Whole number 0 has no predecessor.

MathematicsClass 6CBSE

Write the smallest whole number.

0 is the smallest whole number.

MathematicsClass 6CBSE

If you’re on a diet and have a breakfast consisting of 150 calories, a lunch consisting of 350 calories, and a dinner consisting of 1000 calories, then find the sum of the calories consumed that day.

Breakfast consisting of 150 calories.Lunch consisting of 350 calories.Dinner consisting of 1000 calories.The sum of the calories consumed that day is 150 + 350 + 1000 = 1500 calories.

MathematicsClass 6CBSE

Find the product by suitable rearrangement:8 × 391 × 1252 × 1234 × 50

I. 8 × 391 × 125 = 391 × (125 × 8)= 391 × 1000= 391,000II. 2 × 1234 × 50 =1234 × (2 × 50)= 1234 × 100= 123,400

MathematicsClass 6CBSE

A taxi driver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs Rs.44 per litre, how much did he spend in all on petrol?

Petrol filled on Monday = 40 liters.Petrol filled the next day = 50 liters.∴ Total petrol filled on the two days = 40 liters + 50 liters = 90 liters.∴ Cost of petrol per liter = Rs. 44∴ Cost of 90 liters petrol = Rs. 44 × 90 = Rs. 3960.

MathematicsClass 6CBSE

Write the next three consecutive whole numbers of the following numbers:393598632157

The next three consecutive whole numbers of 39359 are: 39360, 39361, 39362The next three consecutive whole numbers of 8632157 are: 8632158, 8632159, 8632160.

MathematicsClass 6CBSE

Complete pattern1 1 = 111 11 = 121111 111 = _______1111 1111 = 1234321

12321

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