Two metals X and Y form the salts XSO4 and Y2SO4, respectively. The solution of salt XSO4 is blue in colour whereas that of Y2SO4 is colourless. When barium chloride solution is added to XSO4 solution, then a white precipitate Z is formed along with a salt which turns the solution green. And when barium chloride solution is added to Y2SO4 solution, then the same white precipitate Z is formed along with colourless common salt solution.
(a) What could the metals X and Y be?
(b) Write the name and formula of salt XSO4.
(c) Write the name and formula of salt Y2SO4.
(d) What is the name and formula of white precipitate Z?
Write the name and formula of the salt which turns the solution green in the first case.

Question

Two metals X and Y form the salts XSO4 and Y2SO4, respectively. The solution of salt XSO4 is blue in colour whereas that of Y2SO4 is colourless. When barium chloride solution is added to XSO4 solution, then a white precipitate Z is formed along with a salt which turns the solution green. And when barium chloride solution is added to Y2SO4 solution, then the same white precipitate Z is formed along with colourless common salt solution.
(a)	What could the metals X and Y be?
(b)	Write the name and formula of salt XSO4.
(c)	Write the name and formula of salt Y2SO4.
(d)	What is the name and formula of white precipitate Z?
Write the name and formula of the salt which turns the solution green in the first case.

MyClass24 · Accepted Answer

Copper is Metal X and Metal Y is Both forms sulphate salts on reaction
Copper sulphate, CuSO4is XSO4, the salt formed which is blue in colour
Sodium sulphate, Na2SO4 is Y2SO4 which is a colourless salt
Barium sulphate, BaSO4 is Z which is a white precipitate formed upon the reaction when barium chloride is added to copper sulphate and turns the solution green
Copper chloride, CuCl2 is the salt having yellowish brown colour which turns the solution green