A train starting from rest attains a velocity of 72 km/h in 5 minutes. Assuming the acceleration is uniform, calculate the acceleration in m/s².

Initial velocity (u) = 0 m/s (since it starts from rest)
Final velocity (v) = 72 km/h
Convert v to m/s: 72 km/h * (1000 m / 1 km) * (1 h / 3600 s) = 20 m/s
Time (t) = 5 minutes
Convert t to seconds: 5 minutes * 60 seconds/minute = 300 seconds

Using the first equation of motion: v = u + at
20 = 0 + a * 300
20 = 300a
a = 20 / 300 = 1 / 15 m/s² ≈ 0.0667 m/s².