1. A current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in 16 seconds would be roughly
(a) 1020
(b) 1016
(c) 1018
(d) 1023

Question

1.	A current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in 16 seconds would be roughly
(a)	1020
(b)	1016
(c)	1018
(d)	1023

Accepted Answer

Soln:
Answer is (a) 1020
Explanation:
I = Q/t Q= It
Q= 1 x 16
Q= 16 q
Q=ne
n = Q/e
n = 16 /1.6 x 10-19
n = 10 x 1019
n = 1020 electrons
The number of electrons flowing is 1020 electrons

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