1. A current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in 16 seconds would be roughly (a) 1020 (b) 1016 (c) 1018 (d) 1023
ScienceClass 10CBSEAnswered 27 Mar 2026
Answer
Soln:
Answer is (a) 1020
Explanation:
I = Q/t Q= It
Q= 1 x 16
Q= 16 q
Q=ne
n = Q/e
n = 16 /1.6 x 10-19
n = 10 x 1019
n = 1020 electrons
The number of electrons flowing is 1020 electrons