1. A compound C (molecular formula, C2H4O2 ) reacts with Na - metal to form a compound R and evolves a gas which burns with a pop sound. Compound C on treatment with an alcohol A in presence of an acid forms a sweet smelling compound S (molecular formula, C3H6O2 ). On addition of NaOH to C, it also gives R and water. S on treatment with NaOH solution gives back R and A. Identify C, R, A, S and write down the reactions involved.
ScienceClass 10CBSEAnswered 27 Mar 2026
Answer
- Compound C is Ethanoic acid[Acetic acid]
It reacts with sodium metal to form a compound called R . R is Sodium Ethanoate. 2CH3COOH +2 Na 2CH3COONa+H2
conc, H2SO4
- CH3COOH +C2H5OH CH3COOC2H5 + H20
so compound S is Ester or Ethyl ethanoate and compound A is Ethanol 3)CH3COOC2H5+NaoH CH3COONa + C2H5OH.
so compound R is again Sodium Ethanoate. So compound C is Ethanoic acid
A is Ethanol
S is EsterR is sodium Ethanoate.